MP bisects ∠BMS. If m∠BMP = 2x + 9 and m∠BMS = 7x – 3, find the value of m∠PMS
1 answer:
Answer:
Step-by-step explanation:
If MP bisects ∠BMS, then the line MP divides <BMS equally;
The adition postulate if therefore true;
<BMP +< PMS = <BMS and <BMP = < PMS
The equation becomes;
<BMP +< BMP= <BMS
2 <BMP = <BMS
2(2x+9) = 7x - 3
4x+18 = 7x-3
collect like terms
4x-7x = -3-18
-3x = -21
x = 21/3
x = 7
Since <BMP = < PMS 2x+9
< PMS = 2(7)+9
< PMS = 14+9
< PMS = 23
Hence the value of < PMS is 23
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