x would equal 24
24/2 - 24/3 = 4
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
Option A
Step-by-step explanation:
Y is the amount of back pack
The total amount is represented by m
If Y is the cost of back pack purchased by Oliver, then 0.7 Y is the tax applicable on the purchase of back pack
Hence, the remaining cost would be total amount with Oliver minus the cost of back pack and the tax applicable on the purchase of back pack
Remaining cost = m - (y + 0.07y)
Hence, option A is correct
Answer:
So if Charlie only has $27 to spend and hes already buying $3 kid's meal that leaves him with $24 to spend for 6 sandwiches. If you divide 6 by 24, 24/6 leaves him with $4 to spend on each sandwich.
Step-by-step explanation:
Answer:
This cannot be simplified any further. That is the simplest you'll get.
