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Phoenix [80]
4 years ago
11

Please help me!.!.!.!.!

Mathematics
2 answers:
tiny-mole [99]4 years ago
8 0
3 3 over 32 because it's the only one 4 and 8 can go to!
ipn [44]4 years ago
8 0
2 3/4 = 11/4        1 /8 = 9/8
11/4 % 9/8 = 11/4 x 8/9
so
the answer is 2 4/9
 


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Prove that 3:8 is equivalent to 12:32
Anarel [89]
Prove that 3:8 is equivalent to 12:32: I'd suggest that you write the ratio 12:32 as<span /><span><span><span><span><span><span><span><span><span>12</span><span /></span><span><span>32</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span></span> and then factor both the 12 and the 32. Write out the factors:<span /><span><span><span><span><span><span><span><span><span>12</span><span /></span><span><span>32</span><span /></span><span><span /><span /></span></span></span><span>=</span><span><span><span><span><span>(</span><span>?</span><span>)</span><span>(</span><span>?</span><span>)</span></span><span /></span><span><span><span>(</span><span>?</span><span>)</span><span>(</span><span>?</span><span>)</span></span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span></span> and then reduce this last result by cancelling out the common factor.3 x 4 = 12
8 x 4 = 32
It is equivalent. They both multiplied by four the get that ratio.
8 0
3 years ago
Which equation results from applying the secant and tangent segment theorem to the figure? 12(a 12) = 102 10 12 = a2 10(a 10) =
Solnce55 [7]

The equation which results from applying the secant and tangent segment theorem to the figure is

10(a+10)=(12)^2

<h3>What is secant and tangent segment theorem?</h3>

The secant-tangent theorem tells the relation of the line segment made by a tangent and the secant lines with the connected circle.

According to this theorem, if the tangent and secant segments are drawn from an exterior point, then the square of this tangent segment is equal to the product of the secant segment and the line segment from that exterior point.

In the figure attached below for the circle O, the length of the DB is,

DB=10

Here, the line segment AB is a unit. Thus, the length of line segment AD is,

AD=a+10

The length of the tangent DE is 12 units. Thus, by the above theorem,

(DE)^2=AB\times BD\\(12)^2=(a+10)\times10\\

Hence, the equation which results from applying the secant and tangent segment theorem to the figure is

10(a+10)=(12)^2

Learn more about the secant-tangent segment theorem here;

brainly.com/question/10732273

4 0
2 years ago
Taxi driver charges $3.50 for pickup, plus an additional $.20 per mile. What is the constant of this situation?
kaheart [24]

Answer:

3.50

Step-by-step explanation:

doesnt change therefore its constant


brainliest answer please


6 0
3 years ago
Read 2 more answers
What is the absolute value for 3.45?​
Lady bird [3.3K]

Answer:

∣∣3.45∣∣=3.45

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
3/√3 how to get final answer?<br><br> Is it like this <br> 3=√3*√3<br><br> And <br> √3*√3/√3= √3
Tresset [83]

Answer:

\sf   \sqrt{3}

Step-by-step explanation:

\sf =  \frac{3}{ \sqrt{3} }

\sf =  \frac{3}{ \sqrt{3} }  \times  \frac{ \sqrt{3} }{ \sqrt{3} }

\sf =  \frac{3 \sqrt{3} }{( \sqrt{3} \times  \sqrt{3})  }

\sf =  \frac{3 \sqrt{3} }{3}

\sf =  \frac{ \cancel{3} \sqrt{3} }{ \cancel3}

\sf =  \sqrt{3}

8 0
3 years ago
Read 2 more answers
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