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4 years ago

Please help me!.!.!.!.!

Mathematics

2 answers:

tiny-mole [99]4 years ago

8 0

3 3 over 32 because it's the only one 4 and 8 can go to!

ipn [44]4 years ago

8 0

2 3/4 = 11/4 1 /8 = 9/8
11/4 % 9/8 = 11/4 x 8/9
so
the answer is 2 4/9

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P=-30h+74 The variable h represents the number of hours he has spent reading, the variable p represents the number of pages left

olchik [2.2K]

Answer: Ethan will have to spend 2 hours reading if 14 pages are left to read

Step-by-step explanation:

Given the equation

P=-30h+74

where p =number of pages left to read and

h= the number of hours he has spent reading

Therefore , if Ethan has 14 pages left to read, then the number of hours Ethan will have to read will be

P=-30h+74

14= -30h + 74

30h= 74-14

30h= 60

h = 60/30

h =2 hours

Ethan will have to spend 2 hours reading if 14 pages are left to read

6 0

3 years ago

PLZZZ HELP ME OUT THIS DUE RIGHT NOW AND I FREAKING OUT PLEASE HELP ME P.S YOU HAVE WRITE ANSWERS FOR ALL OF THEM

Nimfa-mama [501]

Answer:

a is greater than 1, so a−1 is positive.

The distance between a and 1 appears to be less than the distance between 1 and 0, so it looks like a is less than 2. Thus a−2 is negative.

b is negative, so −b is positive.

The distance between a and 0 appears to be less than the distance between b and 0, so it looks like |a| is less than |b|. Since b is negative and a is positive, a+b is negative.

a−b = a+−b. Since b is negative, −b is positive. a is also positive. Thus, a−b is positive.

Since |a| and |b| are both greater than 1, |ab| is also greater than 1 (this builds on the intuition students gained in fifth grade as in 5.NF.5). ab is negative since a is positive and b is negative. Thus, ab+1 is negative.

8 0

3 years ago

Read 2 more answers

I rlly need help!!!!!!!

Yuliya22 [10]

The correct answer is the 2nd one

3 0

3 years ago

A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o

balu736 [363]

Answer:

$P(X \ge 1) = 0.509$

$P(X \ge 1) = 0.6807$

Step-by-step explanation:

From the question we are told that

The number of students in the class is N = 20 (This is the population )

The number of student that will cheat is k = 3

The number of students that he is focused on is n = 4

Generally the probability distribution that defines this question is the Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally probability mass function is mathematically represented as

$P(X = x) = \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}$

Here C stands for combination , hence we will be making use of the combination functionality in our calculators

Generally the that he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

Here

$P(X \le 0) = \frac{ ^{3} C_0 * ^{20 - 3} C_{4- 0}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ ^{3} C_0 * ^{17} C_{4}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ 1 * 2380}{ 4845}$

$P(X \le 0) = 0.491$

Hence

$P(X \ge 1) = 1 - 0.491$

$P(X \ge 1) = 0.509$

Generally the that he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

$P(X \ge 1) =1- [ \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]$