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Allushta [10]
1 year ago
15

Type the correct answer in each box. If necessary, use / for the fraction bar. Find the solution to this system of equations. It

y = 1 21-y+z = 1 1+2y+z IL y = = Reset Next

Mathematics
1 answer:
sertanlavr [38]1 year ago
5 0

ANSWER

• x = 1/3

,

• y = 2/3

,

• z = 1

EXPLANATION

There are many methods to solve a linear system of equations, but in this case we have to use the substitution method -which consists in clearing one variable as a function of the other/s and replace in another equation. For a system of three variables such as this one, we have to do this twice:

1° clear x from the first equation:

\begin{gathered} x+y=1 \\ x=1-y \end{gathered}

Replace x by this expression in the second equation:

\begin{gathered} 2x-y+z=1 \\ 2(1-y)-y+z=1 \end{gathered}

Note that now we have two variables, y and z. Before the next step we have to rewrite the equation above so that we only have one y:

\begin{gathered} 2\cdot1-2y-y+z=1 \\ 2-3y+z=1 \end{gathered}

2° clear y from the equation above:

\begin{gathered} -3y+z=1-2 \\ -3y=-1-z \\ y=\frac{-(1+z)}{3} \\ y=\frac{1+z}{3} \end{gathered}

And replace y by this expression in the last equation. Note that the third equation also contains x, so we have to replace first x as a function of y like in the first step:

\begin{gathered} x+2y+z=\frac{8}{3} \\ (1-y)+2y+z=\frac{8}{3} \end{gathered}

Rewrite it so we only se one y:

\begin{gathered} 1-y+2y+z=\frac{8}{3} \\ 1+y+z=\frac{8}{3} \end{gathered}

And now we replace y by the expression we found in the second step:

1+\frac{1+z}{3}+z=\frac{8}{3}

So now we have one equation with one variable. Let's solve for z:

\begin{gathered} 1+\frac{1}{3}+\frac{z}{3}+z=\frac{8}{3} \\ \frac{4}{3}+\frac{4z}{3}=\frac{8}{3} \\ \frac{4z}{3}=\frac{8}{3}-\frac{4}{3} \\ \frac{4z}{3}=\frac{4}{3} \\ z=1 \end{gathered}

We have that z = 1.

The next steps are to back replace and find the other variables. Remember that in the second step we had y as a function of z:

y=\frac{1+z}{3}

Replace z = 1 and solve:

y=\frac{1+1}{3}=\frac{2}{3}

y = 2/3

And finally, replace y = 2/3 in the expression of the first step, where we found x as a function of y:

x=1-y=1-\frac{2}{3}=\frac{1}{3}

and we got x = 1/3

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(b) P(X < $46,000) = 0.1423

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Step-by-step explanation:

We are given that U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542.

Suppose annual salaries in the metropolitan Boston area are normally distributed with a standard deviation of $4,246.

<em>Let X = annual salaries in the metropolitan Boston area</em>

SO, X ~ Normal(\mu=$50,542,\sigma^{2} = $4,246^{2})

The z-score probability distribution for normal distribution is given by;

                      Z  =  \frac{X-\mu}{\sigma }  ~ N(0,1)

where, \mu = average annual salary in the Boston area = $50,542

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(a) Probability that the worker’s annual salary is more than $57,000 is given by = P(X > $57,000)

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                                                                     = 1 - 0.93574 = <u>0.0643</u>

<em>The above probability is calculated by looking at the value of x = 1.52 in the z table which gave an area of 0.93574</em>.

(b) Probability that the worker’s annual salary is less than $46,000 is given by = P(X < $46,000)

    P(X < $46,000) = P( \frac{X-\mu}{\sigma } < \frac{46,000-50,542}{4,246 } ) = P(Z < -1.07) = 1 - P(Z \leq 1.07)

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<em>The above probability is calculated by looking at the value of x = 1.07 in the z table which gave an area of 0.85769</em>.

(c) Probability that the worker’s annual salary is more than $40,000 is given by = P(X > $40,000)

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