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The sign of the product of -35 and -625 is positive, negative, or zero

IRISSAK [1]

Answer:

Positive

Step-by-step explanation:

The product of two negative numbers has a positive sign, whereas the product of a positive and a negative number is negative.

Since -35 and -625 are both negative, they would have a positive sign for their product.

Hope this helps.

7 0

3 years ago

Alexandria,a car dealer,earns 40% commission of her luxury vehicles sales. Last year,her sales were $480,000. What was the total

Oxana [17]

Answer:

$12,000,000

Step-by-step explanation:

To find her commission, create a proportion.

$\frac{40}{100}=\frac{480000}{x}$

To solve use cross multiplication.

40(x) = 100(480000)

40x = 48000000

x= 12,000,000

3 0

4 years ago

Read 2 more answers

For every 10,000 gallons of pool water, there needs to be 1 gallon of liquid chlorine. Steve has a 55,000 gallon pool. How much

Rudik [331]

Answer:

5.5 Gallons

Step-by-step explanation:

6 0

3 years ago

The volume of a right circular cone with radius r and height h is V = pir^2h/3.

Scorpion4ik [409]

The question is incomplete. The complete question is :

The volume of a right circular cone with radius r and height h is V = pir^2h/3. a. Approximate the change in the volume of the cone when the radius changes from r = 5.9 to r = 6.8 and the height changes from h = 4.00 to h = 3.96.

b. Approximate the change in the volume of the cone when the radius changes from r = 6.47 to r = 6.45 and the height changes from h = 10.0 to h = 9.92.

a. The approximate change in volume is dV = _______. (Type an integer or decimal rounded to two decimal places as needed.)

b. The approximate change in volume is dV = ___________ (Type an integer or decimal rounded to two decimal places as needed.)

Solution :

Given :

The volume of the right circular cone with a radius r and height h is

$V=\frac{1}{3} \pi r^2 h$

$dV = d\left(\frac{1}{3} \pi r^2 h\right)$

$dV = \frac{1}{3} \pi h \times d(r^2)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

a). The radius is changed from r = 5.9 to r = 6.8 and the height is changed from h = 4 to h = 3.96

So, r = 5.9 and dr = 6.8 - 5.9 = 0.9

h = 4 and dh = 3.96 - 4 = -0.04

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (5.9)(4)(0.9)+\frac{1}{3} \pi (5.9)^2 (-0.04)$

$dV=44.484951 - 1.458117$

$dV=43.03$

Therefore, the approximate change in volume is dV = 43.03 cubic units.

b). The radius is changed from r = 6.47 to r = 6.45 and the height is changed from h = 10 to h = 9.92

So, r = 6.47 and dr = 6.45 - 6.47 = -0.02

h = 10 and dh = 9.92 - 10 = -0.08

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (6.47)(10)(-0.02)+\frac{1}{3} \pi (6.47)^2 (-0.08)$

$dV=-2.710147-3.506930$

$dV= -6.22$

Hence, the approximate change in volume is dV = -6.22 cubic units

8 0

3 years ago

Please help me with these problems; geometry is really getting on my nerves. T-T

ivolga24 [154]

For #19 part A :

By vertical angles and then same side interior angles 3x + 2x = 180
5x = 180
x = 36

For #19 part B:

You are correct with the 35, but you missed the fact that the 105 angle is supplementary with the unknown angle inside the triangle. So:

180 - 105 = 75

Then:

180 = 35 + 75 + x
180 = 110 + x
x = 70

Last question:

Do you know what the symbol means? Text me and tell me and I can answer it for you. :)

7 0

3 years ago

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