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Airida [17]
3 years ago
7

What is surface area?

Mathematics
2 answers:
strojnjashka [21]3 years ago
7 0

Answer:

The total area of the surface of a 3D object.

Step-by-step explanation:

topjm [15]3 years ago
5 0

Answer:

where is the question please

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A marketing company surveys 100 males and 100 females between the ages of 55 and 70 to determine how many times they text each d
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Answer: I believe that A is the correct answer.

On average, females text more than males.

Step-by-step explanation:

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4 years ago
Find the area of the figure
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3 years ago
9. Ellie is making a batch of pancakes
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4 0
3 years ago
the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 a
Furkat [3]

Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau} (Eq. 1)

Where:

\frac{dm}{dt} - First derivative of mass in time, measured in miligrams per year.

\tau - Time constant, measured in years.

m - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt

\ln m = -\frac{1}{\tau} + C

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (Eq. 2)

Where:

m_{o} - Initial mass of isotope, measured in miligrams.

t - Time, measured in years.

And time is cleared within the equation:

t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right]

Then, time constant can be found as a function of half-life:

\tau = \frac{t_{1/2}}{\ln 2} (Eq. 3)

If we know that t_{1/2} = 5730\,yr and \frac{m(t)}{m_{o}} = 0.35, then:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.35

t \approx 8678.505\,yr

The wood was cut approximately 8679 years ago.

5 0
3 years ago
Can somebody please help me with these?
alexdok [17]

Answer:

r=52, v=9.96, a=-8.5 all calculated

6 0
3 years ago
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