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mylen [45]
3 years ago
14

Which two answers???

Mathematics
1 answer:
Norma-Jean [14]3 years ago
6 0

Answer:

B and D

Step-by-step explanation:

have a nice day and mark me brainliest! :)

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Kipton puts one marshmallow on the scale and it weighs 7.2 grams. How much would 10 marshmallows weigh?
Maksim231197 [3]

Answer:

72 grams

Step-by-step explanation:

7.2 x 10 = 72

7 0
3 years ago
HURRY!!!!!!! Which symbol replaces ? to make the statement true? 16÷4+12 ? 4+24÷2 A.< B.= C.>
satela [25.4K]
16 / 4 + 12 ___ 4 + 24/2
4 + 12 ___ 4 + 12
16 __ 16

u need an equal sign because 16 = 16
3 0
3 years ago
Read 2 more answers
which three numbers make a right triangle the square root of 4 the square root of 5 the square root of 9 + square root of 6 the
statuscvo [17]
Please, group your sets of numbers, using {   }  notation or at least semicolons ( ; ).  Thanks.

Looking at what I think is your first set:   { sqrt(4), sqrt(5), sqrt(16) }

Square each of these and then subst. the results into the Pythagorean Theorem:

  { 4, 5, 16 }        Do 4 and 5 when added together result in 16?  NO.
Therefore,   { sqrt(4), sqrt(5), sqrt(16) }  does not produce a right triangle.

Your turn.  Pick out the next 3 numbers and test them using the Pyth. Thm.               
8 0
3 years ago
X
Veseljchak [2.6K]
Sorry fdont really no
3 0
3 years ago
Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are
Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

.

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}.

Recall that \binom{n}{k}= \frac{n!}{k!(n-k)!} In this case, the student passes if X is at least four correct questions, then

P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696

c)The expected value of a binomial random variable with parameters n and p is E[X] = np. IN our case, n=6 and p =0.2. Then the expected value of correct answers is 6\cdot 0.2 = 1.2

5 0
3 years ago
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