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Neko [114]
3 years ago
10

write an equation of the line that passes through the given point(-2,5) and is parallel to the given line 2y=4x-6

Mathematics
1 answer:
iragen [17]3 years ago
6 0
Y=2x+b

substitute -2 for x and 5 for y
5=2(-2)+b4

Solve for b
b=9

The equation is 
y=2x+9

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dolphi86 [110]

So since the vertex falls onto the axis of symmetry, we can just solve for that to get the x-coordinate of both equations. The equation for the axis of symmetry is x=\frac{-b}{2a}, with b = x coefficient and a = x^2 coefficient. Our equations can be solved as such:

y = 2x^2 − 4x + 12: x=\frac{4}{2*2}=\frac{4}{4}=1

y = 4x^2 + 8x + 3: x=\frac{-8}{2*4}=\frac{-8}{8}=-1

In short, the vertex x-coordinate's of y = 2x^2 − 4x + 12 is 1 while the vertex's x-coordinate of y = 4x^2 + 8x + 3 is -1.

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