Answer:
It is a function
Step-by-step explanation:
A function is of the form:
![\left[\begin{array}{c}y_1&y_2&y_3\\-&-&-\\y_n\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dy_1%26y_2%26y_3%5C%5C-%26-%26-%5C%5Cy_n%5Cend%7Barray%7D%5Cright%5D)
Where each of the x values must be distinct.
The x values are referred to as domain while the y values are called range.
Having said that, the given data can be represented as follows:
----------- ![\left[\begin{array}{c}7&-8&-6\\-8&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D7%26-8%26-6%5C%5C-8%262%5Cend%7Barray%7D%5Cright%5D)
<em>From the representation above, none of the x values are repeated.</em>
<em>Hence, it is a function</em>
Answer: 3
Step-by-step explanation:
12c+14=50
-14 -14
Cross out positive and negative 14
50-14= 36
Bring down 12c=36
Divide 12 on both sides of equation
Bring down c
36Divide by 12 is 3
The given triangle is a right-angled triangle. This means that special trig identities can be applies
<u>These identities are as follows:</u>
sin (theta) = opposite / hypotenuse
cos (theta) = adjacent / hypotenuse
tan (theta) = opposite / adjacent
<u>Now, for the unknown theta in the triangle:</u>
The opposite side is 16 and the hypotenuse is 20
This means that we will use the <u>sin</u> not the cos as Bob did
<u>The solution will be as follows:</u>
sin (theta) = opposite / hypotenuse
sin (theta) = 16 / 20
theta = sin^-1(16/20)
theta = 53.13°
Hope this helps :)
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SO you would have to first have the surface area of the cube which is 25 for each side so 25 x 6 = 150
Then you find the surface area for the other sides and It is 4 x 5 divided by two for each triangle on the side, so that would be 20 and you multiply then 6.4 x 5 to equal 32 for the rectangle. The last part is the bottom and it is 4 x 5 again which is 20 so then you add them all up but im not sure.