Question

Find the quotient and the remainder: (x^2+3x-4)/(x-1)

Answer 1

Evaluate this...
$\frac{x^2+3x-4}{x-1}$
the x at the bottom cancels out one of the xs at the top so it will be
$\frac{x^2+2x-4}{-1}$
Now the one cancels out one of the 1s in the -4 so
${x^2+2x-3}$

Hope this helps :)