Answer:Perimeter of a rectangle is 2*the length plus 2*the width
P = 2L + 2W and P = 130, so
L + W = 65
Three times the length is equal to 10 times the width, giving
3L = 10W
Substituting into the above for L = 65 – W,
3(65 – W) = 10W
195 – 3W = 10W
195 = 13W
W = 195/13 = 15
W = 15 yards,
And L = (10/3)W = (10/3)*15 = 50
L = 50 yards
Step-by-step explanation:
Explanation
In the image, we are given the diameter of the circle as 20 mi. The area of the circle will be calculated as;
Answer
Answer:
The upper bound for the perimeter of the rectangle = 427.76 cm
Step-by-step explanation:
To obtain the upper bound for the perimeter, we need to first obtain the upper bound for the Length and Breadth of the rectangle.
Since, these dimensions were rounded to the nearest 1 decimal place, we can write down their ranges
Length = 127.3 cm
Width = 86.5 cm
Length can range from 127.25 cm to 127.34 cm
Breadth can range from 86.45 cm to 86.54 cm
The upper bound for the Length and Breadth of the rectangle are this 127.34 cm and 86.54 cm respectively.
Perimeter = 2 (L + B)
Upper bound of the perimeter
= 2 × (127.34 + 86.54)
= 2 × 213.88
= 427.76 cm
Hope this Helps!!!
Answer:
the answer is "d" because the x region is negative 2 and the y region is a positive1
Answer: b
Step-by-step explanation: because there were only four friends
