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Rina8888 [55]
3 years ago
9

The speed-time graph shows the first 30 minutes of another train journey. The distance travelled is 100km. The maximum speed of

the train is V km/h
Find V

Mathematics
1 answer:
aalyn [17]3 years ago
4 0

The question is missing the graph. So, the graph is attached below.

Answer:

The maximum speed of the train is V=240\ km/h

Step-by-step explanation:

Given:

Distance travelled is 100 km.

Time interval is 30 minutes.

We know that, area under the curve of a speed-time graph gives the total distance travelled by the train.

The area under the curve is the area of the given trapezium shape shown in the graph below.

The height of the trapezium is equal to the maximum speed of the train represented by 'V' km/h. The parallel sides are of lengths equal to (25 - 5 =) 20 min and (30 - 0 =) 30 min.

Converting the units of parallel sides from minutes to hours we get:

30\ min=\frac{30}{60}=\frac{1}{2}\ h\\20\ min=\frac{20}{60}=\frac{1}{3}\ h

Now, area of a trapezium is given as:

Area=\frac{1}{2}\times\textrm{Sum of parallel sides}\times \textrm{Height}\\\\Area=\frac{1}{2}(\frac{1}{2}+\frac{1}{3})(V)\\\\Area=\frac{1}{2}(\frac{3+2}{6})(V)\\\\Area=\frac{1}{2}(\frac{5}{6})(V)\\\\Area=(\frac{1\times 5}{2\times6})(V)\\\\Area=\frac{5}{12}(V)

Now, area under the curve is equal to the distance travelled. So,

\frac{5}{12}(V)=100\\V=\frac{100\times12}{5}\\V=240\ km/h

Therefore, the maximum speed of the train is V=240\ km/h

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3 years ago
Nemecek Brothers make a single product on two separate production lines, A and B. Its labor force is equivalent to 1000 hours pe
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Answer:

(a) The inequality for the number of items, x, produced by the labor, is given as follows;

250 ≤ x ≤ 600

(b) The inequality for the cost, C is $1,000 ≤ C ≤ $3,000

Step-by-step explanation:

The total time available for production = 1000 hours per week

The time it takes to produce an item on line A = 1 hour

The time it takes to produce an item on line B = 4 hour

Therefore, with both lines working simultaneously, the time it takes to produce 5 items = 4 hours

The number of items produced per the weekly labor = 1000/4 × 5 = 1,250 items

The minimum number of items that can be produced is when only line B is working which produces 1 item per 4 hours, with the weekly number of items = 1000/4 × 1 = 250 items

Therefore, the number of items, x, produced per week with the available labor is given as follows;

250 ≤ x ≤ 1250

Which is revised to 250 ≤ x ≤ 600 as shown in the following answer

(b) The cost of producing a single item on line A = $5

The cost of producing a single item on line B = $4

The total available amount for operating cost = $3,000

Therefore, given that we can have either one item each from lines A and B with a total possible item

When the minimum number of possible items is produced by line B, we have;

Cost = 250 × 4 = $1,000

When the maximum number of items possible, 1,250, is produced, whereby we have 250 items produced from line B and 1,000 items produced from line A, the total cost becomes;

Total cost = 250 × 4 + 1000 × 5 = 6,000

Whereby available weekly outlay = $3000, the maximum that can be produced from line A alone is therefore;

$3,000/$5 = 600 items = The maximum number of items that can be produced

The inequality for the cost, C, becomes;

$1,000 ≤ C ≤ $3,000

The time to produce the maximum 600 items on line A alone is given as follows;

1 hour/item × 600 items = 600 hours

The inequality for the number of items, x, produced by the labor, is therefore, given as follows;

250 ≤ x ≤ 600

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In a recent poll, 778 adults were asked to identify their favorite seat when they fly, and 492 of them chose a window seat. Use
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Answer:

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

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Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

Step-by-step explanation:

1) Data given and notation

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X=492 represent the people that chose a window seat.

\hat p=\frac{492}{778}=0.632 estimated proportion of people that chose a window seat.

p_o=0.5 is the value that we want to test

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Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the majority of adults prefer window seats when they fly:  

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.632 -0.5}{\sqrt{\frac{0.5(1-0.5)}{778}}}=7.36  

4) Statistical decision  

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The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

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