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oksano4ka [1.4K]
3 years ago
12

Angie and kenny play online video games. Angie biys 1 software package and 4 months of game play. Kenny buys 1 software package

and 1 month of game play. Each software costs $35. If their total cost is $130 what is thr cost of one month of game play
Mathematics
1 answer:
Elenna [48]3 years ago
8 0

Answer:

1 month of game play will cost $12

Step-by-step explanation:

Here in this question, we are interested in calculating the cost of one month of game play.

From the question, we know the following;

Angie bought 1 software package and 4 months of game play

while

Kenny bought 1 software package and 1 month of game play.

The total packages and months bought will be;

2 packages and 5 months of game play

From the question, we are told that 1 month of game play is $35, so 2 months of game play will be 2 * $35 = $70

So the amount remaining for the 5 months will be; $130 - $70 = $60

So if 5 months cost $60, it means one month will be $60/5 = $12

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Expand and simplify<br> (x + 1)(x + 7)
zheka24 [161]

Answer: 10x + 7

Step-by-step explanation:

multiply everything

2x + 7x + x + 7

combine like terms

10x + 7

7 0
3 years ago
Given teo circles whose radii are 9" and 24", the ratio of thuer circumfrence is?
saul85 [17]

Answer:

The ratio is 3:8

Step-by-step explanation:

The circumference of a circle can be calculated using the formula;

C = 2 * pi * r

for 9 inches;

C = 2 * pi * 9 = 18 pi inches

For 24 inches;

C = 2 * pi * 24 = 24 pi inches

The ratio is thus;

18 pi : 48 pi

divide through by 6 pi

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5 0
3 years ago
Mary Jane is buying paper plates for her big going away party. The fancy plates come in packs of 8. She is inviting 41 guests. H
inessss [21]

41 guests / 8 plates = 5.125 packs

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8 0
3 years ago
Read 2 more answers
How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the
miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

<h3>8d.</h3>

\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}

___

<h3>9b.</h3>

\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}

___

<h3>10b.</h3>

\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}

Neither solution makes any denominator be zero, so both are good solutions.

8 0
3 years ago
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