A leg of a right triangle can never be greater then the hypotenuse
this formula will tell you if it's a valid right triangle
![{?}^{2} + {?}^{2} = {?}^{2}](https://tex.z-dn.net/?f=%20%7B%3F%7D%5E%7B2%7D%20%2B%20%7B%3F%7D%5E%7B2%7D%20%3D%20%7B%3F%7D%5E%7B2%7D%20)
the first two question marks are the legs of the triangle while the one after the = is the hypotenuse.
THE STEPS:
![{3}^{2} + { \sqrt{7}^{2} } = {4}^{2}](https://tex.z-dn.net/?f=%20%7B3%7D%5E%7B2%7D%20%2B%20%7B%20%5Csqrt%7B7%7D%5E%7B2%7D%20%7D%20%3D%20%7B4%7D%5E%7B2%7D%20)
![9 + {2.65}^{2} = 16](https://tex.z-dn.net/?f=9%20%2B%20%7B2.65%7D%5E%7B2%7D%20%3D%2016)
![{2.65}^{2} = 7](https://tex.z-dn.net/?f=%20%7B2.65%7D%5E%7B2%7D%20%3D%207)
![9 + 7 = 16](https://tex.z-dn.net/?f=9%20%2B%207%20%3D%2016)
ANSWER:
-3 since parallel lines have equal slopes
Answer:
y = x + 2
Step-by-step explanation:
Step 1: Find the slope
![m=\frac{y2-y1}{x2-x1} = \frac{6-1}{4-(-1)}=\frac{6}{6} =1](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By2-y1%7D%7Bx2-x1%7D%20%3D%20%5Cfrac%7B6-1%7D%7B4-%28-1%29%7D%3D%5Cfrac%7B6%7D%7B6%7D%20%3D1)
Step 2: Substitute the slope and a point in to find y intercept
(6)=(1)(4)+b
6 = 4 + b
b = 2
Step 3: Substitute all the information in
y = x + 2
Therefore the equation for a line that passes through (4,6) and (-1,1) is y = x + 2
The answer to the question.
Download photomath it solves and shows the steps