Answer:
A. x = 11/16
Step-by-step explanation:
For the purpose here, it is convenient to rearrange the equation to f(x) -g(x) = 0. We know the root will be in the interval [0, 1] because (f-g)(0) = -3 and (f-g)(1) = +3. At each iteration, we evaluate (f-g)(x) at the midpoint of the interval to see which of the interval end points can be moved and still bracket the root.
Using the bisection method starting with the interval [0, 1] we find f(1/2)-g(1/2) < 0, so we can move the interval limits to [1/2, 1].
For the next iteration, we find f(3/4) -g(3/4) > 0, so we can move the interval limits to [1/2, 3/4].
For the third iteration, we find f(5/8) -g(5/8) < 0, so we can move the interval limits to [5/8, 3/4].
Then the root is approximately the middle of that interval:
x ≈ (5/8 +3/4)/2 = 11/16
_____
This value of x is 0.6875. The root is closer to 0.639802004233. The bisection method takes about 3 iterations for each decimal place of accuracy. Other methods can nearly double the number of accurate decimal places on each iteration.
Answer:
the time is 1.57 sec and the distance is 49.32mm
Step-by-step explanation:
Given that,
The angle is 180°
Angular velocity is 2rev/sec
The radius is 10mm
we are to find the time and distance traveled at that time
The formula is
θ = at
where t is the time,
a is the angular velocity
θ is angle in radian
so,
θ = 180° × π/180°
θ = π
= 3.14
Hence ,
θ = at
3.14 = 2t
t = 1.57sec
let the distance be xmm
Therefore , the time is 1.57 sec and the distance is 49.32mm
[6, ∞) , x >= 6 so
answer is D. last one
6<= x < ∞
Answer:
(x - 3)² + (y + 9)² = 25
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k ) are the coordinates of the centre and r is the radius
Given area = 25π , that is
πr² = 25π ( divide both sides by π )
r² = 25 ( take the square root of both sides )
r = = 5
With centre (h, k) = (3, - 9 ) and r = 5 , then
(x - 3)² + (y - (- 9) )² = 5² , that is
(x - 3)² + (y + 9)² = 25