Hello,
Use the factoration
a^2 - b^2 = (a - b)(a + b)
Then,
x^2 - 81 = x^2 - 9^2
x^2 - 9^2 = ( x - 9).(x + 9)
Then,
Lim (x^2- 81) /(x+9)
= Lim (x -9)(x+9)/(x+9)
Simplity x + 9
Lim (x -9)
Now replace x = -9
Lim ( -9 -9)
Lim -18 = -18
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The second method without using factorization would be to calculate the limit by the hospital rule.
Lim f(x)/g(x) = lim f(x)'/g(x)'
Where,
f(x)' and g(x)' are the derivates.
Let f(x) = x^2 -81
f(x)' = 2x + 0
f(x)' = 2x
Let g(x) = x +9
g(x)' = 1 + 0
g(x)' = 1
Then the Lim stay:
Lim (x^2 -81)/(x+9) = Lim 2x /1
Now replace x = -9
Lim 2×-9 = Lim -18
= -18
Intuitively, one would think the ball would land in the green spot 2 out of the 38 times, since there are 38 slots and 2 are green.
The probability that it lands in a green section is 2/38. Multiplying this by the number of times the experiment is performed, we get (2/38)(38) = 2.
Answer:
1. -18x+6
multiply everything inside with the number outside the bracket
2. -18x-6
same as number one
3. 18x-12
same as number one
4. -18x-6
same as number one
for 5 I can't see it well but it should be similar
you just need to substitute what's outside the bracket to what Is inside the bracket
Answer:
x=1 if that's 15 x
Step-by-step explanation:
The
correct answer is:
TrueExplanation:
1.
(Straightforward)
2.
(log to base of itself is always 1)
3.
(Using log power property)
Hence the correct option is True.
