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mina [271]
3 years ago
15

Which answer is the correct form of bar notation for this decimal number: 4.676767…

Mathematics
2 answers:
kkurt [141]3 years ago
8 0

Answer:

4.67 with the bar notation above the 67

Step-by-step explanation:

To solve this correctly you need to recall the rules repeating decimal numbers and what bar notation looks like. but i forgot my answer so its not above 6

Rudiy273 years ago
4 0
Hello There!

Well all of your answer options are the same so i suppose they are all right.

Hope This Helps You!
Good Luck :)
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In the drawing g>h. which statement about the volumes of the two cylinders is true
Contact [7]

Answer:

The bottom option for ttm

Step-by-step explanation:

The volume of the left-hand cylinder is less than the volume of the right-hand cylinder.

7 0
3 years ago
There is more than 1 answer and I already know 1 answer which is 3/4 but I don't know the rest. Please help!
andriy [413]

Answer:

9/12

Step-by-step explanation:

3/4 times 3 = 9/12

3/4 is equivalent to 9/12 so those would be the two anwsers

3 0
2 years ago
A=9,b=-24 <br> Evaluate a +b for the given valus
aliina [53]

Step-by-step explanation:

A + b

Putting value of a and b

9 + (-24)

9 - 24

= - 15

7 0
3 years ago
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
Quiz Questions
gavmur [86]
1. 6:3
2. 6:2
3. 3:18
4:5:6
5:13
6:x
7:x
8: check
9:check
10: x
6 0
2 years ago
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