To find the gradient of the tangent, we must first differentiate the function.
The gradient at x = 0 is given by evaluating f'(0).
The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so
Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).
So the point (0, -1) lies on the tangent. Substituting into the tangent equation:
Answer:
Yes; the compass was kept at the same width to create the arcs for points C and D.
Step-by-step explanation:
When bisecting a segment by hand the steps are:
-Place the compass on one of the endpoints and open the compass to a distance more than halfway across the segment.
-Swing an arc on either side of the segment.
-Keeping the compass at the same width, place the compass on the other endpoint and swing arcs on either side so that they intersect the first two arcs created.
-Mark the intersection points of the arcs and draw a line through those two points.
-The point where this new line crosses the given segment is the midpoint and divides the segment in half.
Its not b because segment c and d was created when you marked the intersection points of the arcs and just drew a line through those two points; They didn't use a straightedge. its not C because this does demonstrate how to bisect a segment by hand, Also the compass was kept at the same width to create the arcs for points C and D. Its not D because this does demonstrate how to bisect a segment by hand, Also a straightedge was not used to create segment CD.
Answer:
I can't answer your question because I can't see what boxes your talking about
Answer:
B
Step-by-step explanation:
( point E)
