Calculate the area of triangle ABC with altitude CD, given A(6,-2) B(1,3) C(5,5) D(2,2)
1 answer:
The area will be half the product of the lengths of AB and CD.
|AB| = √((6-1)² +(-2-3)²) = 5√2
|CD| = √((5-2)² +(5-2)²) = 3√2
Area = (1/2)*(5√2)*(3√2) = (1/2)*(15*2) = 15
The appropriate choice is ...
D: 15 square units
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