Hello from MrBillDoesMath!
Answer:
11/ 1009 (.0109 approximately)
Discussion:
99/9081 = => as 9081 = 9 * 1009 = 3 * 3 * 1009
99/ ( 3 * 3 * 1009) =
(99/(3*3)) * (1/1009) =
(99/9) * (1/1009) =
11/ 1009 =
.0109 approximately
Thank you,
MrB
I ain't Joseph but what's wrong?
Answer:
d. 55 feet /sec^2
Step-by-step explanation:
Average acceleration is ...
a = ∆v/∆t = (116 ft/s -6 ft/s)/(2 s)
= 110/2 ft/s^2 = 55 ft/s^2
