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koban [17]
3 years ago
5

A circular merry-go-round has a radius of 5 feet. Find the distance of a spin of one full rotation. Use 3.14 for pi and round th

e answer to nearest tenths. *
A 15.7 ft
B 78.5 ft
C 31.4 ft
D 28 ft
Mathematics
1 answer:
Sedbober [7]3 years ago
6 0

Option C

The distance of a spin of one full rotation is 31.4 feet

<em><u>Solution:</u></em>

Given that,

A circular merry-go-round has a radius of 5 feet

Radius = 5 feet

We have to find the distance of spin for one full rotation

Distance covered in 1 full of rotation is equal to circumference of circle

<em><u>The circumference of circle is given as:</u></em>

C = 2 \pi r

Where "r" is the radius

C = 2 \times 3.14 \times 5\\\\C = 6.28 \times 5\\\\C = 31.4

Thus the distance of a spin of one full rotation is 31.4 feet

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2 years ago
Solve the following system of equations by substitution
WITCHER [35]

Answer:

(-1, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

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  5. Division
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<u>Algebra I</u>

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y = 2x + 3

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<u>Step 2: Solve for </u><em><u>x</u></em>

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  1. Substitute in <em>y</em>:                                                                                                  2x + 3 = x + 2
  2. [Subtraction Property of Equality] Subtract <em>x</em> on both sides:                         x + 3 = 2
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<u>Step 3: Solve for </u><em><u>y</u></em>

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3 0
3 years ago
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Just answer # 1 please
Rudiy27
Can't see the photo fully! Sorry!
4 0
3 years ago
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