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koban [17]
3 years ago
5

A circular merry-go-round has a radius of 5 feet. Find the distance of a spin of one full rotation. Use 3.14 for pi and round th

e answer to nearest tenths. *
A 15.7 ft
B 78.5 ft
C 31.4 ft
D 28 ft
Mathematics
1 answer:
Sedbober [7]3 years ago
6 0

Option C

The distance of a spin of one full rotation is 31.4 feet

<em><u>Solution:</u></em>

Given that,

A circular merry-go-round has a radius of 5 feet

Radius = 5 feet

We have to find the distance of spin for one full rotation

Distance covered in 1 full of rotation is equal to circumference of circle

<em><u>The circumference of circle is given as:</u></em>

C = 2 \pi r

Where "r" is the radius

C = 2 \times 3.14 \times 5\\\\C = 6.28 \times 5\\\\C = 31.4

Thus the distance of a spin of one full rotation is 31.4 feet

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---------------------------------------------------
---------------------------------------------------

Explanation:

Let L be the length of rectangle B
There are two copies of L (along the top and bottom of the rectangle). The vertical pairs of sides are both 7x each.

For the triangle, we have three sides of 12x since this is an equilateral triangle. All three sides are congruent for any equilateral triangle.

The perimeter of the triangle is
P = s1+s2+s3
P = 12x+12x+12x
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Since both perimeters are the same, this means 
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So the length of the rectangle, in terms of x, is 11x. This is the final answer.

Note: if we knew the value of x, then we could find the numeric value of the length for the rectangle. But since we don't know x, we leave it as 11x.

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a factory produced 6911 boxes of ice cream after 135 boxes of ice cream were sold, the factory produced 347 more of ice cream .h
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There are 7123 boxes of ice cream left in the factory

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