768 ÷ 32 = 24
32 × 24 = 768
I hope this helps you!!
please make my answer brainliest to help me out!!!!
Thanks!!
Correct Question:
Which term could be put in the blank to create a fully simplified polynomial written in standard form?
![8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y3](https://tex.z-dn.net/?f=8x%5E3y%5E2%20-%5C%20%5B%5C%20%5C%20%5D%20%2B%203xy%5E2%20-%204y3)
Options

Answer:

Step-by-step explanation:
Given
![8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y^3](https://tex.z-dn.net/?f=8x%5E3y%5E2%20-%5C%20%5B%5C%20%5C%20%5D%20%2B%203xy%5E2%20-%204y%5E3)
Required
Fill in the missing gap
We have that:
![8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y^3](https://tex.z-dn.net/?f=8x%5E3y%5E2%20-%5C%20%5B%5C%20%5C%20%5D%20%2B%203xy%5E2%20-%204y%5E3)
From the polynomial, we can see that the power of x starts from 3 and stops at 0 while the power of y is constant.
Hence, the variable of the polynomial is x
This implies that the power of x decreases by 1 in each term.
The missing gap has to its left, a term with x to the power of 3 and to its right, a term with x to the power of 1.
This implies that the blank will be filled with a term that has its power of x to be 2
From the list of given options, only
can be used to complete the polynomial.
Hence, the complete polynomial is:

Answer:
75600
Step-by-step explanation:
We are given that a word MATHEMATICS
Total letters =11
M repeated 2 times
T repeated 2 times
A repeated 2 times
Total vowels=4
Let MTHMTCS=P
Total number of ways in which MTHMTCS can be arranged=
PAEAI
Total number of ways in which PAEAI can arranged=
Total number of arrangements when all consonant appear together=
Total number of arrangements when all consonant appear together=
By using formula ;
9514 1404 393
Explanation:
When something is subtracted from both sides of the equation, the justification is the <em>subtraction property of equality</em>. When something multiplies both sides of the equation, the justification is the <em>multiplication property of equality</em>. (This should not be a mystery.)
Here, the equation is solved by subtracting 17/3, then subtracting 1/2x, then multiplying by the inverse of the coefficient of x. After each of these steps is a simplification.

