We need a system of equations to solve this. "Difference" is to subtract, and we are taking this difference of the 2 squared unknowns to be 20. That equation is

. Our "first number is x^2, so 3 times that is 3x^2. "Increased by" is adding to that first number. What we are adding is the second number. The second equation is

. Let's solve the first equation for x^2:

and sub that value for x^2 into the second equation.

and

. Subtract 60 from both sides and combine the y^2 terms to get

. Divide both sides by 4 to get y^2 = 16 and y = 4. Let's go back now and solve for x. We will use the fact that y^2 = 16 to solve for x^2 and then take the square root of it.

, x^2 = 4, so x = 2. Your solutions are x = 2 and y = 4. There you go!
8 ones , 9 tens , 4 hundreds , 5 thousands , 9 ten thousands
Answer:
![\\\sqrt[1]{8}](https://tex.z-dn.net/?f=%5C%5C%5Csqrt%5B1%5D%7B8%7D)
![\sqrt[1]{8}](https://tex.z-dn.net/?f=%5Csqrt%5B1%5D%7B8%7D)
Step-by-step explanation:
Answer:
her score is lower after removing the highest and lowest value
just took the test
Answer:
x = 1.53, -1.53.
Step-by-step explanation:
9x^2 - 21 = 0
9x^2 = 21
x^2 = 21/9
x = +/- √21 / 3
x = 1.53, -1.53.