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zalisa [80]
3 years ago
6

PLZ HELP FAST!!! will mark brainliest, What is the best approximation for the circumference of a circle with a diameter of 500 k

m? Use 3.14 to approximate pi.
785 km

1570 km

3140 km

3725 km
Mathematics
1 answer:
NikAS [45]3 years ago
7 0
Hey there,

So, we need to remember that the circumference of a circle is \pi3.14

So this means that we would do  500×3.14.

And by this we do. . 

Firstly, work out 4 × 500. As mentioned before, we can ignore the decimal point for now. The smaller figures in green are the tens figures carried over. Working from right to left:

4 × 0 = 0

4 × 0 = 0

4 × 5 = 20

<span>Put the 0 in the appropriate column and carry the 2.
</span>
We now work out 10 × 500.
This can be written as 1 × 500 × 10.

Because we are multiplying by 10, we place 1 zero to the right and then work out 1 × 500.

1 × 0 = 0

1 × 0 = 0

<span>1 × 5 = 5
</span>
Lastly, work out 300 × 500.
This can be written as 3 × 500 × 100.

Because we are multiplying by 100, we place 2 zeroes to the right and then work out 3 × 500.

3 × 0 = 0

3 × 0 = 0

3 × 5 = 15
<span>
Put the 5 in the appropriate column and carry the 1


</span>Finally the 3 rows are added together starting at the right. The smaller figures in green are the tens figures carried over.

0 + 0 + 0 = 0

0 + 0 + 0 = 0

0 + 0 + 0 = 0

0 + 5 + 2 = 7

5 = 5

1 = 1

How is the decimal point positioned? 3.14 has 2 digits after the decimal point.

The final answer must also have 2 digits after the decimal point.

<span>So: 500 × 3.14 = </span>\boxed{1570.00}

~Jurgen

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shutvik [7]

Answer:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = \frac{1}{4}

Step-by-step explanation:

Given that

3 white, 2 blue and 5 gray shirts are there.

To find:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = ?

Solution:

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First of all, let us learn about the formula of an event E:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(First\ White) = \dfrac{\text{Number of white shirts}}{\text {Total number of shirts left}}

P(First\ White) = \dfrac{3}{10}

Now, this shirt is set aside.

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P(First\ White\ and\ second\ gray) = P(First White) \times P(Second\ Gray)\\\Rightarrow P(First\ White\ and\ second\ gray) = P(First White) \times \dfrac{\text{Number of gray shirts}}{\text{Total number of shirts left}}\\\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{3}{10} \times \dfrac{5}{9}\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow P(First\ White\ and\ second\ gray) = \bold{\dfrac{1}{4} }

So, the answer is:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = \frac{1}{4}

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