The ratio of interest can be found for collinear points by considering only one of the coordinates. Let's look at the x-coordinates.
(Tx -Mx)/(Dx -Mx) = (1-(-3))/(9-(-3)) = 4/12 = 1/3
Then the ratio of interest is MT:MD = 1:3.
Answer:
16x^2 - 49y^2 = 784
Step-by-step explanation:
as we know that this is the standard equation of hyperbola bcz 1 coordinate of vertices is 0.
since in vertices x coordinate is present and y coordinate is 0 so Tranverse axis of hyperbola is along x axis .
vertices in general = (a,0) and (-a,0)
vertices given = ( 7,0) and (-7 , 0)
so a=7
similarly
co vertices in general = ( 0 , b) and ( 0 , -b)
co vertices given = ( 0, 4) and (0 , -4)
so,
b= 4
now equation for x axis is:
(x2/a2) - ( y2/b2) = 1
by putting values we observe the ans is
16x^2 - 49y^2 = 784
The answer to this question is:
9x+8/3x^2
(-4n)^5 because there are five of them.
Im pretty sure its C
hoped i helped