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EleoNora [17]
3 years ago
13

C

Mathematics
1 answer:
AlexFokin [52]3 years ago
7 0

Answer:

36

Step-by-step explanation:

making tally marks for every skittles and mms???

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Diana worked on her science project for 6 1 3 hours. Gabe worked on his science project 1 3 4 times as long as Diana. Paula work
Vaselesa [24]
Are your numbers right?  Diana worked on her project for 613 hours, Gabe worked on it for 134 times as long as Diana, and Paula worked on her science project 34 times as long as Diana?  Assuming they are, It is false that Diana worked longer on her science project than Gabe worked on his.  Tell me if I read the question wrong, I am happy to help.
4 0
3 years ago
The following data shows wind speed in a city, in miles per hour, on consecutive days of a month:
shusha [124]
In the data shown, rearranging the  data [<span>9.4, 9.2, 9.7, 9.8, 9.4, 9.7, 9.6, 9.3, 9.2, 9.1, 9.4] from the least to the greatest would give us the following data set:

9.1, 9.2, 9.2, 9.3, 9.4, 9.4, 9.4, 9.6, 9.7, 9.7, 9.8

The box-plots uses a 5-number summary. The minimum value, then Q1 which is the media of the lower half of the set, Q2 which is the median of the total set, Q3 which is the median of the upper half of the set, and Q4 which is the highest number. Among the choices, the correct answer is B.</span>
8 0
3 years ago
I need help with this there is part a and b
Alex17521 [72]

Answer:

the answer should be 3.914 or 4

Step-by-step explanation:

hope it helps!

I am guessing that Part A: 3.914

and                          Part B: 4

6 0
3 years ago
Select True or False for each statement.
SSSSS [86.1K]

\left( \dfrac 1 {64} \right)^{- 5/6} =64^{5/6} = (\sqrt[6]{64})^5 = 2^5 =32

TRUE

\sqrt[5]{36^4}=36^{4/5}

which surely isn't 36.  FALSE

\sqrt{12} - \dfrac 2 5 \sqrt{75} = 2 \sqrt{3} -\dfrac 2 5 (5) \sqrt{3} = 0

FALSE

For the fourth one we have a

\sqrt{98b} + \sqrt{2b}

which isnt

10\sqrt{b}

so this is FALSE.

\dfrac{1}{(\sqrt 5 - \sqrt 6)^2}

= \dfrac{1}{(\sqrt 5 - \sqrt 6)^2} \cdot \dfrac{(\sqrt 5 + \sqrt 6)^2}{(\sqrt 5 + \sqrt 6)^2}

= \dfrac{(\sqrt 5 + \sqrt 6)^2}{ ( (\sqrt 5 - \sqrt 6)(\sqrt 5 + \sqrt 6))^2}

= \dfrac{(\sqrt 5 + \sqrt 6)^2}{( 5-6)^2}

=(\sqrt 5 + \sqrt 6)^2

No fractions in that one so FALSE.

3 0
2 years ago
Who tryin to talk thats not in there feelins
sp2606 [1]

Answer:

me :/

Step-by-step explanation:

5 0
2 years ago
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