The midpoint is the average of the endpoints.
((-11+i) + (-4+4i))/2 = -15/2 +5/2i
The letters in MATH can be arranged 16 ways. D.
Answer:
she got 27 dollars
Step-by-step explanation:
when u add $4 and $14 u get $18.then add the 9 dollars she had left and u will get 27 dollars.
Hope this is a clear description
Answer:

And the z score for 0.4 is

And then the probability desired would be:

Step-by-step explanation:
The normal approximation for this case is satisfied since the value for p is near to 0.5 and the sample size is large enough, and we have:


For this case we can assume that the population proportion have the following distribution
Where:


And we want to find this probability:

And we can use the z score formula given by:

And the z score for 0.4 is

And then the probability desired would be:

Answer:
Option D
Step-by-step explanation:
correct answer on edge :)