1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Triss [41]
3 years ago
8

Use the stem-and-leaf plot below to answer the question. What is the range of data?

Mathematics
2 answers:
yaroslaw [1]3 years ago
6 0
Hello!

The range is the lowest number subtracted from the highest

The highest is 96
The lowest is 54

96 - 54 = 42

The range is 42

Hope this helps!
nevsk [136]3 years ago
3 0
96-54= 42. So 42 would be the range of this set of data.
You might be interested in
1) Two numbers are in the ratio 5: 6. If 8 is added to each of the numbers, they will be in the ratio 7: 8. Find the numbers.
Mashutka [201]

Answer:

(the answer to 1 is20:24) (and 2 is 51)

7 0
3 years ago
You start at (8,0). You move left 6 units. Where do you end?​
tamaranim1 [39]

Answer:

(2, 0)

Step-by-step explanation:

Moving left just subtracts from the x coordinate (example: left 8 subtracts 8 from the x coordinate)

Brₐinliest plz so close to leveling up

3 0
3 years ago
Read 2 more answers
Karina is creating two pyramids with the nets below using construction paper. In both nets, all of the triangular faces of the p
sleet_krkn [62]

Answer:

144 sq in

Step-by-step explanation:

Face height=9, bases=6 in

#Assume the pyramid has a square base.

First we need to calculate the perpendicular height of the pyramid:

#Pythagorean \ Theorem\\a^2+b^2=c^2\\9^2-(0.5\times 6)^2=h^2\\72=h^2\\h=\sqrt{72} \ in

Now to find the surface area of each pyramid:

A=lw+l\sqrt{(w/2)^2+h^2}+w\sqrt{(l/w)^2+h^2}\\\\\#w=l=6,h=\sqrt{72}\\\\A=6^2+6\sqrt{(6/2)^2+72}+6\sqrt{(6/6)^2+72}\\\\A\approx 144\ sq \ in

Hence amount of construction paper needed to make each pyramid is 144 sq in

3 0
3 years ago
Find A and B if the graph of Ax + By = 12 passes through (2,1) and is parallel to the graph of 2x - 7y = 3
Ivenika [448]

Answer:

24-21

Step-by-step explanation:

2×12=24 7×3=21 I started from 2×2 towards 2×12 when I got the answer and I started 7×1 towards 7×3

4 0
3 years ago
Based on the estimated cost of college from step 1, determine how you are going to pay for college. You will need to do some res
Nezavi [6.7K]

This is a budgeting exercise. Based on the estimated cost of college which was set at $58,000, the following steps indicate how I intend to pay for college:

  • Scholarship - 70%   = $40,600
  • Work Study - 17.2% = $10,000
  • Loan - 12.76%         <u> = $7, 400</u>

                                        <u>$58,000</u>

<h3>What is budgeting?</h3>

Budgeting is simply the process of outlining the total expense requirements of an individual person or a corporate entity and how those expenses will be satisfied and efficiently allocated.

From the above, the total sum of $58,000 will be satisfied from three sources:

  • Scholarships
  • Work-Study; and
  • Loan.

Learn more about budgeting at;

brainly.com/question/24940564
#SPJ1

             

8 0
2 years ago
Other questions:
  • a student measured the temperature in degrees celsius for several winter days and recorded the data in a list find the average o
    7·2 answers
  • Find two z values, one positive and one negative, that are equidistant from the mean so that the areas in the two tails add to t
    11·1 answer
  • How should i do this?
    15·1 answer
  • Mrs. Eaton's class is participating in the "Box Tops for Education" campaign. On the first day, her
    12·2 answers
  • Simplify. (fg^2 )^4
    12·2 answers
  • Find the area of the shaded
    11·1 answer
  • The objective is to
    14·1 answer
  • Hii please help asap ill give brainliest thanks
    7·1 answer
  • 572 cars were parked in a parking garage. The same number of cars was parked on each floor. If there were 4 floors, how many car
    7·2 answers
  • 8th GRADE MATH
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!