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Orlov [11]
3 years ago
12

Select the equations of the lines that are parallel to the line whose equation is y = 3x + 5.

Mathematics
1 answer:
Orlov [11]3 years ago
3 0
The slope-intercept form of the equation of a straight line:

y=mx+b

m=slope
Therefore; in this equation (y=3x+5); m=3

a)
6x+2y=12
2y=-6x+12
y=-6/2 x + 12/2
y=-3x+6  ⇒            m=-3≠3  (this line is not parallel to "y=3x+5")

b)
-3x+y=8
y=3x+8      ⇒          m=3 (this line es parallel to "y=3x+5")    

c)
3y=9x
y=9/3 x
y=3x          ⇒            m=3 (this line is parallel to "y=3x+5")

d)
y=-x            ⇒           m=-1≠3 (this line is not parallet to "y=3x+5")

Therefore; "-3x+y=8" and "3y=9x" are parallel to "y=3x+5".
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<h3>Given</h3>

P = 3r + 2s

<h3>Find</h3>

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<h3>Solution</h3>

First of all, look at how this is evaluated in terms of what happens to a value for s.

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To solve for s, you undo these operations in reverse order. The "undo" for addition is adding the opposite. The "undo" for multiplication is division (or multiplication by the reciprocal).

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... P - 3r = 2s . . . . . . -3r is added to both sides to undo addition of 3r

... (P -3r)/2 = s . . . . . both sides are divided by 2 to undo the multiplication

Note that the division is of everything on both sides of the equation. That is why we need to add parentheses around the expression that was on the left—so the whole thing gets divided by 2.

Your solution is ...

... s = (P - 3r)/2

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