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Orlov [11]
3 years ago
12

Select the equations of the lines that are parallel to the line whose equation is y = 3x + 5.

Mathematics
1 answer:
Orlov [11]3 years ago
3 0
The slope-intercept form of the equation of a straight line:

y=mx+b

m=slope
Therefore; in this equation (y=3x+5); m=3

a)
6x+2y=12
2y=-6x+12
y=-6/2 x + 12/2
y=-3x+6  ⇒            m=-3≠3  (this line is not parallel to "y=3x+5")

b)
-3x+y=8
y=3x+8      ⇒          m=3 (this line es parallel to "y=3x+5")    

c)
3y=9x
y=9/3 x
y=3x          ⇒            m=3 (this line is parallel to "y=3x+5")

d)
y=-x            ⇒           m=-1≠3 (this line is not parallet to "y=3x+5")

Therefore; "-3x+y=8" and "3y=9x" are parallel to "y=3x+5".
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2 years ago
Look at this system of equations.<br> 2x +5 =9.5<br> 3x + 5y =10.5<br> What is the value of x+y
stiv31 [10]

Answer:

x = 2.25 y = 0.75

Step-by-step explanation:

2x = 9.5- 5

2x = 4.5

x = 4.5 ÷ 2

x = 2.25

know we now what is x so in the second one we evaluate x

3(2.25) + 5y = 10.5

6.75 + 5y = 10.5

5y = 10.5- 6.75

5y = 3.75

y = 3.75 ÷ 5

y = 0.75

that's it !

if you want to check your answer you can evaluate x and y so it will be like

2×2.25 + 5

= 4.5 + 5 = 9.5

and

3× 2.25 +5×0.75

= 6.75 + 3.75 = 10.5

6 0
3 years ago
Sabeena had 15 3/4m long ribbon. She cut into two pieces such that the length of one pieces is 9 1/2m. Find the length of other
DochEvi [55]

Answer:

6 1/4

Step-by-step explanation:

Total length of the ribbon= 15 3/4 m= 63/4 m

One piece= 9 1/2 m= 19/2 m

Other piece length =X

X= 63/4-19/2

  =63/4-38/4

  =25/4

  =6 1/4

3 0
2 years ago
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Lesechka [4]
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6 0
3 years ago
Untaxi viaja
juin [17]

Answer:

60 millas por hora.

Step-by-step explanation:

Dado que un taxi viaja  a una velocidad de 48 mph  para llegar a un destino en 2 horas y media, para determinar cuál seria su velocidad si se tarda dos horas para llegar ​se debe realizar el siguiente cálculo:

48 x 2.5 = 120

120 / 2 = X

60 = X

Así, su velocidad, si se tardase dos horas en llegar, sería de 60 millas por hora.

7 0
2 years ago
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