we have
Min=26
Q1=67
Q2=80
Q3=87
Max=100
Mean=76
Mode=100
standard deviation=76
IQR=20
so
In this problem
the mean is equal to the standard deviation
therefore
<h2>The standard deviation is incorrectly</h2>
Answer:
A B and D
Step-by-step explanation:
Answer:
28.3 feet
Step-by-step explanation:
Given a tree 41.8 feet tall casts a shadow that is 27 feet long
So the Tangent of the angle of the sahdow remains the same for the both trees.
We know that 
Therefore the height of the tree is 28.3 feet
Y=a(x-h)^2+k
vertex form is basically completing the square
what you do is
for
y=ax^2+bx+c
1. isolate x terms
y=(ax^2+bx)+c
undistribute a
y=a(x^2+(b/a)x)+c
complete the square by take 1/2 of b/a and squaring it then adding negative and postive inside
y=a(x^2+(b/a)x+(b^2)/(4a^2)-(b^2)/(4a^2))+c
complete square
too messy \
anyway
y=2x^2+24x+85
isolate
y=(2x^2+24x)+85
undistribute
y=2(x^2+12x)+85
1/2 of 12 is 6, 6^2=36
add neagtive and postivie isnde
y=2(x^2+12x+36-36)+85
complete perfect square
y=2((x+6)^2-36)+85
distribute
y=2(x+6)^2-72+85
y=2(x+6)^2+13
vertex form is
y=2(x+6)^2+13
