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musickatia [10]
3 years ago
11

By graphing the system of constraints find the values or x and y that maximize the objective function, find the maximum value.

Mathematics
1 answer:
Eduardwww [97]3 years ago
4 0
The answer is choice C
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Am i right 5TH GRADE MATH THANKS!​
Genrish500 [490]

Answer:

Step-by-step explanation:

the answer is 7.9

6 0
3 years ago
Read 2 more answers
1. Complete this statment: A polygon with all sides the same length is said to be____
Katen [24]

Answer:

Q1. Regular (A)

Q2. 105° (C)

Q3. x=45°

Step-by-step explanation:

Q1. A regular polygon is a polygon with all sides and angles equal.

Q2. The sum of the measure of exterior angles of a polygon is always 360°. Therefore,  360°-255°=105°

Q3. 148°+112°+(2x+10)°+(2x)°+90°= Sum of angles in a pentagon.

<u><em>Note</em></u>: The square at the fifth angle shows that its a right angle which is 90°. Also all the angles are equal to the sum of angles in a pentagon 'cause the polygon has 5 sides ( a pentagon).

Sum of interior angles of a polygon is: (n-2)180°. Where "n" is the number of sides of the polygon.

Therefore the sum of interior angles is (5-2)180°=540°

solving the equation you have;

360°+4x=540°

4x=540°-360°

4x=180°

x=180°/4

x=45°

therefore x=45°

8 0
3 years ago
Is a relation always a function? Is a function always a relation? Explain.
katen-ka-za [31]

A function is always a relation but relation is not always a function

<u>Solution:</u>

Given that, we have to explain Is a relation always a function and is a function always a relation

Note that both functions and relations are defined as sets of lists.  

In fact, every function is a relation. However, not every relation is a function.  A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y.

That is, given an element x in X, there is only one element in Y that x is related to.

For example, consider the following sets X and Y. Let me give you a relation between them that is not a function;

X = { 1, 2, 3 }

Y = { a , b , c, d }

Relation from X to Y : { (1,a) , (2, b) , (2, c) , (3, d) }

This relation is not a function from X to Y because the element 2 in X is related to two different elements, b and c

Relation from X to Y that is a function: { (1,d) , (2,d) , (3, a) }

This is a function since each element from X is related to only one element in Y. Note that it is okay for two different elements in X to be related to the same element in Y. It's still a function, it's just not a one-to-one function.

So, we can say that function is a type of relation.

Which means whatever a function occurs, it will be a relation from one set to other.

But when a relation occurs it may be a function but need not be always a function.

Hence, a function is always a relation but relation is not always a function.

8 0
3 years ago
What is 30 divide by 4?
Sedaia [141]

Answer:

30 ÷ 4 = <em>7.5</em>

Step-by-step explanation:

This means that:

7.5 fits into 30 4 times

Example:

7.5    +   7.5     +    7.5    +     7.5

 \______\______/_______/

                    30

I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>
7 0
3 years ago
The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
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