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Nikitich [7]
3 years ago
15

Use the given information to draw a box-and-whisker plot of the data set

Mathematics
1 answer:
drek231 [11]3 years ago
7 0

Answer:

The box-and-whisker plot of this distribution is presented in the attached image to this solution.

Step-by-step explanation:

A box plot gives a visual representation of the distribution of the data, showing where most values lie and those values that greatly differ from the rest, called outliers.

A box and whiskers plot shows 5 major information about the distribution of data. It shows:

- The maximum variable.

- The minimum variable.

- The Median.

- The first quartile.

- The third quartile.

Further info such as the range and Inter quartile range can then be obtained from this 5-number summary.

The elements of the box plot are described thus;

The bottom side of the box represents the first quartile, and the top side, the third quartile. Therefore, the width of the central box represents the inter-quartile range.

The horizontal line inside the box is the median.

The lines extending from the box reach out to the minimum and the maximum values in the data set, as long as these values are not outliers. The ends of the whiskers are marked by two shorter horizontal lines.

Variables in the dataset, higher than Q3+(1.5×IQR) or lower than Q1-(1.5×IQR) are considered outliers and are usually shown using dots above the top whisker or below the bottom whisker.

The required boxplot for this question is given in the attached image to this solution.

The median for the boxplot isn't provided, but it was assumed to be midway between the first and third quartile.

Hope this Helps!!!

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What Numbers Go Into The Venn Diagram
antiseptic1488 [7]

Answer:

(a)The total number of outcomes where the sum is 9 or

    greater than 9 is  10

(b)Total number of outcomes where the sum is odd = 18

(c)Total number of outcomes where the  sum greater or equal to 9 and is

     also odd = 6

Step-by-step explanation:

Here, Sample Space = { Sum of the two digits when two dices are thrown together}

or,   S   =   {2,3,4,5,6,7,8,9,10,11,12}

(a)  The number of ordered pairs where sum is  9 or greater than 9

    = { sum is 9  ,  Sum is 10 ,  Sum is 11,   Sum is 12}

    = {(6,3)(3,6),(4,5)(5,4) ,   (5,5), (6,4),(4,6)  , (6,5)(5,6),   (6,6)}

Hence the total number of outcomes where the sum is 9 or

greater than 9 is  10

(b)  The number of ordered pairs where sum is odd.

    = { Sum is 3 ,  Sum is 5,   Sum is 7, Sum is 9, Sum is 11}

    = {(1,2)(2,1),   (4,1)(1,4),(2,3)(3,2) ,   (6,1), (1,6),(5,2),(2,5),(4,3)(3,4)  ,

        (6,3)(3,6), (4,5)(5,4),  (6,5),(5,6)}  = 18

Hence total number of outcomes where the sum is odd = 18

(c) Intersection point refers the outcomes which have sum greater or equal to 9 and is odd

Here, the possible outcomes are  = { Sum is 9 ,  Sum is 11}

                                            ={ (6,3)(3,6), (4,5)(5,4),  (6,5),(5,6)}  = 6

Hence total number of outcomes where the  sum greater or equal to 9 and is also odd = 6

6 0
3 years ago
What is the best estimate for 82% of 503?
AleksAgata [21]
82% of 503 is 412.46 hope this helps
5 0
2 years ago
Persons taking a​ 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a
mihalych1998 [28]

Answer:

y = 4.125x + 496.25

Step-by-step explanation:

Set the data up as points. Then deal with the points.

Givens

(30,620)

(70,785)

y2 = 785

y1 = 620

x2 = 70

x1 = 30

Formula

Slope = (y2 - y1) / (x2 - x1)

Solution

Slope = (785 - 620)/(70 - 30)

Slope = 165 / 40

Slope = 4.125

===================

Now you need the y intercept. Either one of the two given points will give you that.

y = 620

x = 30

m = 4.125

y = mx + b

620 = 4.125*30 + b

620 = 123.75 + b

620 - 123.75 + b

b = 496.25

5 0
3 years ago
We are interested in the dimensions of a certain square a rectangle had length triple the side of this square and width two unit
Sphinxa [80]

Let s be the side length of the square. The dimensions of the rectangle are three times the side of the square (i.e. 3s), and two less than the side of the square (i.e. s-2).

So, the area of this rectangle is

3s(s-2)=3s^2-6s

The area of the square is s^2, and we know that the two areas are the same, so we have

3s^2-6s=s^2 \iff 2s^2-6s=0 \iff 2s(s-3)=0 \iff s=0 \lor s=3

The solution s=0 would lead to the extreme case where the rectangle and the square are actually a point, so we accept the solution s=3.

3 0
2 years ago
Help
Alexxx [7]

Answer:

2034.72

Step-by-step explanation:

i took the k-12 quiz and got the answer-

3 0
3 years ago
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