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nadya68 [22]
4 years ago
11

Find the angle between the vectors. (first find an exact expression and then approximate to the nearest degree.) a = 5, −1, 7 ,

b = −2, 4, 3
Mathematics
1 answer:
Pepsi [2]4 years ago
3 0
A.b=lallbl cos t
a.b=(-2*5)+(-1*4)+(3*7)
a.b=7

lal=√(25+1+49)=5√3
lbl=√(4+16+9)=√29
therefore:
7=5√3×√29 cost
cost=0.1501
t=arccos 0.1501=81.37°
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Evaluate.<br> (-4)=<br> (-7) = 0<br> Please help ASAP!!
denis-greek [22]
  • Answer:

<em>(-4)³ = (-4)(-4)(-4) = 16(-4) = - 64</em>

<em>(-7)² = (-7)(-7) = 49</em>

<em>(-)×(-) = +</em>

<em>(-)×(+) = -</em>

4 0
3 years ago
An isosceles triangle has a base of 8 inches and legs measuring 12 inches how wide is the base of a similar triangle with legs m
VARVARA [1.3K]
If the triangles are similar, the base should be 24 inches. The legs on the first triangle are 12 inches. To get 36 inches (the other triangle), we multiply 12 by 3. 12 x 3 = 36. Because you did that to the legs, you must also do it to the base. 8 x 3 = 24. Therefore, the base of the second triangle is 24 inches.
5 0
4 years ago
Which scenario is most likely the one shown on the graph?
nadezda [96]
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4 0
3 years ago
Read 2 more answers
1) You are designing a new kiddie soccer arena. The area of the rectangular
nikdorinn [45]

Answer:

The length of the rectangular field is 12 ft and the width is 5 ft.

Step-by-step explanation:

The area of a rectangle is:

\text{Area} = \text{length}\times \text{width}

The area of a rectangular field is, <em>A</em> = 60 ft.

The length of the field is:

l = w + 7

Compute the width of the field as follows:

\text{Area} = \text{length}\times \text{width}

60=(w+7)\times w\\\\60=w^{2}+7w\\\\w^{2}+7w-60=0\\

Factorize the last equation by splitting the middle term as follows:

w^{2}+7w-60=0\\w^{2}+12w-5w-60=0\\w(w+12)-5(w+12)=0\\(w-5)(w+12)=0

Now, since the width of rectangular field cannot be negative, the width is 5 ft.

Compute the length as follows:

l = w + 7

 = 5 + 7

 = 12

The length of the rectangular field is 12 ft.

7 0
3 years ago
4. The Bulldog Theater charges $9.10 for each adult ticket and $7.75 for each student ticket. Mrs. Williams purchased 7 tickets
zhuklara [117]

Answer:

Two adult tickets and 5 student tickets

Step-by-step explanation:

Let a=adult tickets   Let s=student tickets

You know that each adult ticket is $9.10 and each student ticket cost $7.75. At the end, it cost $56.95 for both students and adults so the first equation should be 9.10a+7.75s=56.95. To get the second equation, you know that Mrs. Williams purchased 7 tickets in total that were both students and adults. Therefore, the second equation should be a+s=7. The two equations are 9.10a+7.75s=56.95

a+s=7.

Now, use substitution to solve this. I will isolate s from this equation so the new equation should be s=-a+7. Plug in this equation to the other equation, it will look like this 9.10a+7.75(-a+7)=56.95. Simplify this to get 9.10a-7.75a+54.25=56.95. Simplify this again and the equation will become 1.35a=2.70. Then divide 1.35 by each side to get a=2. This Mrs. Williams bought two adult tickets. Plug in 2 into a+s=7, it will look like this (2)+s=7. Simplify this and get s=5. This means Mrs. Williams bought five adult tickets. Therefore she bought 2 adult tickets and 5 student tickets.

Hope this helps

4 0
3 years ago
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