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Sunny_sXe [5.5K]
4 years ago
13

Katherine is 35, which is 5 years less than twice fred's age. how old is fred? if f represents fred's age, which equation would

you use to solve this problem?
a. 2f 5 = 35
b. 2f - 5 = 35
c. 35 - 5 = 2f
d. f 5 = 2(30)
Mathematics
1 answer:
Anettt [7]4 years ago
6 0
Your answer would be B, 2f - 5 = 35
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Solve the system algebraically<br> x+3y=11<br> 4x-4y=7
ololo11 [35]

Answer:

x = 65/16,   y = 37/16

Step-by-step explanation:

solve the system algebraically

x+3y=11

4x-4y=7

Try substitution.

let  x =  11 - 3y

Plug in.

4(11 - 3y) - 4y = 7

44 - 12y - 4y = 7

44 - 16y = 7

37 = 16y

y = 37/16

x = 11 - 3*y

x = 11 - 3*(37/16)

x = 11 -  111/16

x = 65/16

6 0
3 years ago
Read 2 more answers
How do I do this? I dont know how to work out his problem
mrs_skeptik [129]

The mom is 36

The twins are 11

1. 58-25= 33

2. 33/3= 11 <----The twins age

3. 11+25= 36 <----The moms age

8 0
3 years ago
You select a sample of 50 scores from a population of 2,000 scores. You compute the range and standard deviation on the sample o
nalin [4]

Answer:

The measure of dispersion which is likely to vary most between your first and second samples is the range.

Step-by-step explanation:

The range and standard deviation of a data are measures of dispersion, i.e. they measure the degree to which the data is dispersed.

The formula to compute the range is:

Range=X_{max}-X_{min}

The formula to compute the sample standard deviation is:

s=\sqrt{\frac{1}{n-1}\sum (X-\bar X)^{2} }

The sample size is: <em>n</em> = 50.

  • As the sample size is large (n = 50 > 30) the sample standard deviation (s) can be used to approximate the population standard deviation (σ). Thus, whatever the sample values be both the standard deviations can be used to approximate the population standard deviation. Hence, it can be said that both the sample standard deviations are approximately equal.
  • Whereas the range of the two samples are very likely to vary since it is based on the minimum and maximum value of the data. For both the samples the minimum and maximum value may be differ. Thus providing different range values.

Thus, the measure of dispersion which is likely to vary most between your first and second samples is the range.

5 0
4 years ago
I do not know the answer plz help
Drupady [299]

Answer:

y < 2 is the inequality of this graph

Step-by-step explanation:

4 0
3 years ago
These are 3 questions btw so i need 3 answers!
monitta

Answer:

<em>y = - </em>\frac{7}{2}<em> cos ( </em>\frac{1}{2}<em> x ) , y = cos ( 3x ) + 2 </em>

Step-by-step explanation:

<u><em>Image 1.</em></u>

The graph is reflection of cosine over x-axis and max is 3.5 ⇒ A = - \frac{7}{2}

Period is ( 4 π ) ⇒ B = \frac{1}{2}

There are no horizontal and vertical shifts ⇒ C = D = 0

<em>y = - </em>\frac{7}{2}<em> cos ( </em>\frac{1}{2}<em> x )</em>

<u><em>Image 3.</em></u>

The graph of cosine shifted 2 units up only ⇒ D = 2 , C = 0

Period of the given function is \frac{2\pi }{3} ⇒ B = 3

<em>y = cos ( 3x ) + 2</em>

6 0
3 years ago
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