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SVEN [57.7K]
3 years ago
15

Find the equation of this line​

Mathematics
1 answer:
Kazeer [188]3 years ago
8 0

Answer:

y= 1x-2

Step-by-step explanation:

The slope is 1.

The y- intercept is (0,-2)

In the equation

y= 1x-2

Hope this helps!

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At the start of a mission, international spy James withdrew $5,000 in Cairo. In Istanbul, he withdrew half of the remaining mone
lord [1]

Answer:

Initial Amount at the start of the mission=\$20000

Step-by-step explanation:

Let initial amount=x

In Cario James withdrew \$5000.

Remaining Amount=x-5000

In Instanbul he with drew half of the remaining amount so half of the remaining amount will be left.

\frac{1}{2}\times(x-5000)=7500\\\\x-5000=15000\\\\x=20000

8 0
3 years ago
If <br><br>f(x)=2(x-3)+4,<br><br>what is:<br><br>f(-2)​
Vlad1618 [11]

Answer:

f(-2) = -6

Step-by-step explanation:

2(-2-3) + 4

2(-5) + 4

-10 + 4

-6

3 0
3 years ago
Find the greatest common factor of the following monomials gh2 2g3h
anzhelika [568]
Hey there :)

gh² and 2g³h

The common here are g and h because the factor g and h appear in both terms

Therefore, the GCF is gh

5 0
3 years ago
Solve the following equation. 4 - 7x 10 = 15 - 6x - 8
Oksana_A [137]
4-70=7-6x
-64-7=6x
-71=-6x
71/6=x
6 0
3 years ago
Read 2 more answers
Community college students conduct a survey at their college. They ask "Do you plan to transfer to a university to pursue a bacc
Tamiku [17]

Answer:

0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

For this case the conditions we have the conditions to assume a normal distribution for the population proportion since:

np=100*0.8=80 >10 , n(1-p) = 10*(1-0.8) =20 >10

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The estimated proportion is given by \hat p =\frac{80}{100} =0.8. If we replace the values obtained we got:

0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

6 0
2 years ago
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