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LuckyWell [14K]
3 years ago
5

You have money in your wallet, but you don't know the exact amount. When a friend asks you, you say that you have 100 dollars gi

ve or take 25. Write an inequality to describe the amount of money in your wallet.
Mathematics
1 answer:
Flauer [41]3 years ago
6 0

Answer: 75 < x < 125.

Step-by-step explanation:

Let x be the amount of money in your wallet.  

The phrase "100 dollars give or take 25" means wallet can have money between (100-25) dollars and (100+25) dollars.

i.e. 100-25 < x < 100+25

⇒ 75 < x < 125.

That means the amount of money in your wallet lies between 75 dollars and 125 dollars.

Hence, the inequality to describe the amount of money in your wallet is 75 < x < 125.

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We might choose to write a recursive formula rather than an explicit formula to define a sequence because (D) the sequence is strictly geometric.

<h3>What is a sequence?</h3>
  • A sequence in mathematics is an enumerated collection of items in which repetitions are permitted and order is important. It, like a set, has members (also called elements, or terms).
  • The length of the series is defined as the number of items (which could be infinite).
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  • The concept of a sequence can be expanded to include an indexed family, which is defined as a function from an index set that may or may not contain integers to another set of elements.

Recursive formulas are commonly used to compute the nth term of a sequence, where a(n) is the sum of all the preceding values.

Using its position, explicit formulas can compute a(n).

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7 0
2 years ago
What is the range of possible sizes for side x
vladimir1956 [14]

Answer:

4<x<12

Step-by-step explanation:

8.0+4.0=12.0

8.0-4.0=4.0 or 4

5 0
2 years ago
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What type of transformation is shown?
Blizzard [7]
Translation is shown.
3 0
3 years ago
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You estimated the average rental cost of a 2 bedroom apartment in Denton. A random sample of 16 apartments was taken. The sample
Zigmanuir [339]

Answer:

The new sample size required in order to have the same confidence 95% and reduce the margin of erro to $60 is:

n=28

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma=160)  

And the distribution for \bar X is:

\bar X \sim N(\mu, \frac{160}{\sqrt{n}})  

We know that the margin of error for a confidence interval is given by:  

Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)  

The next step would be find the value of \z_{\alpha/2}, \alpha=1-0.95=0.05 and \alpha/2=0.025  

Using the normal standard table, excel or a calculator we see that:  

z_{\alpha/2}=\pm 1.96  

If we solve for n from formula (1) we got:  

\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}  

n=(\frac{z_{\alpha/2} \sigma}{Me})^2  

And we have everything to replace into the formula:  

n=(\frac{1.96(160)}{78.4})^2 =16  

And this value agrees with the sample size given.

For the case of the problem we ar einterested on Me= $60, and we need to find the new sample size required to mantain the confidence level at 95%. We know that n is given by this formula:

n=(\frac{z_{\alpha/2} \sigma}{Me})^2  

And now we can replace the new value of Me and see what we got, like this:

n=(\frac{1.96*160}{60})^2 =27.32

And if we round up the answer we see that the value of n to ensure the margin of error required Me=\pm 60 $ is n=28.    

5 0
3 years ago
Waiting Line Models:Movies tonight is a typical video and dvd movie rental outlet for home-viewing customers. During the weeknig
pentagon [3]

Answer:

  1. Probability [No customers in system] = 0.375
  2. Customers waiting for service = 25/24
  3. Average time customer wait = 1.25/1.5
  4. May be wait
  5. Per customer average time = 1.33 (Approx)

Step-by-step explanation:

Given:

Arrival rate λ = 1.25 min

Mean μ = 2

Computation:

(a) Probability [No customers in system]

Probability [No customers in system] = 1-[λ/μ]

Probability [No customers in system] = 1-[1.25/2]

Probability [No customers in system] = 0.375

(b) Customers waiting for service

Customers waiting for service = λ²/ [μ(μ-λ)]

Customers waiting for service = 1.25²/ [2(2-1.25)]

Customers waiting for service = 25/24

(c) Average time customer wait

Average time customer wait = λ / [μ(μ-λ)]

Average time customer wait = 1.25/ [2(2-1.25)]

Average time customer wait = 1.25/1.5

(d) May be wait because Customers waiting for service = 25/24

(e) Per customer average time

Per customer average time = 1/(μ-λ)

Per customer average time = 1/(2-1.25)

Per customer average time = 1.33 (Approx)

7 0
3 years ago
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