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Alexeev081 [22]
3 years ago
9

At the start of a mission, international spy James withdrew $5,000 in Cairo. In Istanbul, he withdrew half of the remaining mone

y. She had $7,500 left. What amount did she have at the start of the mission? Find the initial amount
Mathematics
1 answer:
lord [1]3 years ago
8 0

Answer:

Initial Amount at the start of the mission=\$20000

Step-by-step explanation:

Let initial amount=x

In Cario James withdrew \$5000.

Remaining Amount=x-5000

In Instanbul he with drew half of the remaining amount so half of the remaining amount will be left.

\frac{1}{2}\times(x-5000)=7500\\\\x-5000=15000\\\\x=20000

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A scuba diver starts at 29 meters below the surface and descends until he reaches 67 meters below sea level. How many meters did
KiRa [710]
Answer:
38 meters

explanation:
you subtract 29 from 67
(67-29=38)
3 0
3 years ago
Find quotient 10/6 / 1/ 24
Maru [420]

Answer:

40

Step-by-step explanation:

Quotient means dividing so we must divide 10/6 by 1/24.

10/6 ÷ 1/24

10/6 * 24/1 = 40 <--- Multiply by the reciprocal in order to divide.

Final Answer: 40

I hope this helps! :)

3 0
2 years ago
Which of the following statement is FALSE?
arlik [135]

Answer:

The answer would be A.

Step-by-step explanation:

7 0
3 years ago
Change the fraction 3/4 to a percent.
Levart [38]
There is 100% in 1 since this is three parts of 1 we will have to divide 100 by 4 then multiply it by 3.
After you do all the math you will get 0.75.
You can convert this to a percent by just removing the point and the zero and adding a percent at the end.
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5 0
3 years ago
A point P is moving along the curve whose equation is y = \sqrt x . Suppose that x is increasing at the rate of 4 units/s when x
Mice21 [21]

Answer:3 units/s

Step-by-step explanation:

Given

y=\sqrt{x}

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and \frac{\mathrm{d} x}{\mathrm{d} t}=4 units/s

Distance between Point P and (2,0)

P=\sqrt{(x-2)^2+(\sqrt{x}-0)^2}

P at x=3 P=2

rate at which distance is changing is

\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{\mathrm{d} \sqrt{(x-2)^2+(\sqrt{x}-0)^2}}{\mathrm{d} t}

\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{2x-3}{\sqrt{(x-2)^2+(\sqrt{x}-0)^2}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{2\times 3-3}{2\times 2}\times 4=3 units/s

8 0
3 years ago
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