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bazaltina [42]
3 years ago
12

At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path.The bicyclist headi

ng north is riding 4 km/hour faster than the bicyclist heading south. At 10:30, they are 39 km apart. Find the two bicyclists’ rates.
(A)northbound bicyclist = 15 km/h; southbound bicyclist = 11 km/h
(B)northbound bicyclist = 17 km/h; southbound bicyclist = 11 km/h
(C)northbound bicyclist = 15 km/h; southbound bicyclist = 10 km/h
(D)northbound bicyclist = 16 km/h; southbound bicyclist = 12 km/h
Mathematics
2 answers:
fenix001 [56]3 years ago
5 0

Answer: (A)northbound bicyclist = 15 km/h; southbound bicyclist = 11 km/h

Step-by-step explanation:

Let the speed of the bicycle that is going to the south = x km/h

Thus, according to the question,

The speed of north going bicycle = ( x + 4 ) km/h

Since, they are going opposite to each other,

Hence, the relative speed of the both bicycle = (x + x + 4) km/h = (2 x+ 4) km/h

Now, after crossing each other at 10:30 AM, they are 39 km apart.

⇒ Relative distance = 39 km,

And, the relative time = 1 hour 30 minutes = 1\frac{1}{2} hours = 3/2 hours,

Since,

\text{Relative Speed}= \frac{\text{ Relative Distance }}{\text{Relative time}}

\implies 2x + 4 = \frac{39}{3/2}

\implies 2x+4 = \frac{78}{3}=26

\implies 2x = 22\implies x = 11

Therefore, the speed of south going bicycle = x km/h = 11 km/h

And, the speed of north going bicycle = (x + 4)  km/h = 15 km/h

Oksana_A [137]3 years ago
4 0
The question is asking to choose among the following choices that states the two bicyclist's rate and in my further computation and calculation, I would say that the answer would be letter <span>(A)northbound bicyclist = 15 km/h; southbound bicyclist = 11 km/h. I hope this would help you </span>
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