1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bonufazy [111]
3 years ago
12

What does x equal 7(2x+5)=4x -9 -x PLEASEEEE HELPPPP ME

Mathematics
1 answer:
Gennadij [26K]3 years ago
5 0

Answer: x=-4

Step-by-step explanation:

Given

7(2x+5)=4x-9-x

Expand parenthesis

14x+35=4x-9-x

Combine like terms

14x+35=3x-9

Subtract 35 on both sides

14x+35-35=3x-9-35

14x=3x-44

Subtract 3x on both sides

14x-3x=3x-44-3x

11x=-44

Divide 11 on both sides

11x/11=-44/11

x=-4

Hope this helps!! :)

Please let me know if you have any questions

You might be interested in
How do I prove that 2 cot 2x = cot x-tan x?
BlackZzzverrR [31]
We will start off working on the right hand side. 
<span>cot x - tan x </span>
<span>= [cos x / sin x] - [sin x / cos x] </span>
<span>= [(cos x)^ 2 - (sin x)^2] / [sin x cos x] </span>

<span>This is where it gets a bit tougher if you do not have your formula list with you. </span>
<span>(cos x)^ 2 - (sin x)^2 = cos(2x) </span>
<span>sin 2x = 2 sin x cos x </span>

<span>Note that by arranging the second formula, we will have sin x cos x = (1/2) sin 2x </span>

<span>Hence, we will get: </span>
<span>[(cos x)^ 2 - (sin x)^2] / [sin x cos x] </span>
<span>= [cos 2x] / (1/2)[sin 2x] </span>
<span>= 2[cos 2x] / [sin 2x] </span>
<span>= 2cot 2x </span>
7 0
4 years ago
Solve each equation with the quadratic formula. 4n^2+7n-1=-4
andreyandreev [35.5K]
The answer i got was
n=-3/4,n=-1
7 0
3 years ago
Look at the figures. How can you prove these triangles are congruent?
NNADVOKAT [17]

Answer:

You can use the Side-Angle-Side Postulate.

Step-by-step explanation:

The Side-Angle-Side (or SAS) Postulate basically states that if two sides of two triangles and the included angle are congruent, the two triangles are congruent.

6 0
3 years ago
Ill give brainliest to who ever answers these questions first
svetlana [45]
High blood pressure, high cholesterol, and smoking.
6 0
3 years ago
Read 2 more answers
Which of the functions below could have created this graph?
bearhunter [10]

Answer:

A

Step-by-step explanation:

Two facts need to guide your answer.

One

The highest power is odd: you know this because an even power would start on the left come down do it's squiggles if had any and wind up on the right going up.

This graph comes down on the left does it's squiggles and then goes further down on the right. That's the behavior of something whose highest power is odd.

Two

The leading coefficient,  the number in front of the highest power must be minus. If it was positive as in y = x^3 the graph would be the mirror image of what it is.

Argument

B and D cannot be true. The highest power is even.

C is false because the leading coefficient is + 1.

So that leave A which is the answer.

The graph is included with this answer

7 0
4 years ago
Other questions:
  • Help please!!. <br> Graph the function: f(x) = cos(2x)+1<br> Please plot 5 points on the graph
    14·1 answer
  • Venus buys 13 CDs at 18.99 each. How much does she spend on CDs?
    8·1 answer
  • A store sells cooking oil of two different brands in bottles of the same size. The table below and the equation each show the pr
    14·2 answers
  • Which is a irrational number, √39, √9, √49, 1.7
    8·1 answer
  • What is the definition of exponential growth?
    15·1 answer
  • A fish tank initially contains 15 liters of pure water. Brine of constant, but unknown, concentration of salt is flowing in at 4
    14·1 answer
  • HELP PLEASE HURRY... 56 POINTS
    6·2 answers
  • Please help me answer this question ASAP
    6·1 answer
  • Does the line passing through the points (-3, -6) and (1, 2) intersect the line passing through the points (-4, -1) and (-2, 3)?
    9·2 answers
  • Please i really need help with this
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!