Divide 1440 by 6 to get 240 packs.
<span>First year is 30,000.
</span><span>Earn 5% raise every year.
</span>Growth factor is 1.05 this sounds a lot like a geometric ratio.
An = A1 × r^(n-1)Sn = A1 × (1 - r^n) / (1-r)<span>n = 40
A1 = 30,000
A40 = $30,000 * 1.05^39 = $201,142.53
S40 = A1 * (1 - 1.05^40) / (1-1.05) which becomes:
S40 = 30,000 * -6.039988712 / -.05 which becomes:
</span>S40 = -181,199.6614 / -.05 which becomes:
S40 = $3,623,993.227
<span>The individual yearly calculations are shown below: </span>
Answer:
t=16.2 years
Step-by-step explanation:
A=p(1+r/n)^nt
A=$20100
P=$6500
r=7%=0.07
n=4
t=?
t=ln(A/P)/n {ln(1+r/n)}
=ln(20100/6500) / 4{ln(1+0.07/4)}
=ln(3.0923)/4{ln(1+0.0175)}
=ln(3.0923)/4{ln(1.0175)}
=1.1289/4(0.0174)
=1.1289/0.0696
=16.23
To the nearest tenth
t=16.2 years
It would be a 50/50 chance, because there is only two different things it could land on, and for each there is a 50% chance for it to land on that side so.
The result is
9
a
2
−
16
The reason is the following:
The problem is an example of a notable product: "the sum multiplied by the diference is equal to the difference of squares", that is to say:
(
a
+
b
)
⋅
(
a
−
b
)
=
a
2
−
b
2
.
By applying this to our question, we obtain that:
(
3
a
−
4
)
⋅
(
3
a
+
4
)
=
(
3
a
)
2
−
(
4
)
2
=
9
a
2
−
16
.