(-6)/2=-3 -3+(-6)=-9 so the answer is -9
There are six digits to choose from, but you're only taking three at a time, so the number of such numbers is

The first and last digits can only be even if the number takes the one of the forms "2 _ 8" or "8 _ 2". The middle number can be any of the remaining four, so there is a total of eight such numbers.
This means the probability of getting a number beginning and ending with an even digits is

.
Answer:
b should be it.
Step-by-step explanation:
If

satisfies the ODE

, then

and substituting into the ODE gives

so that the ODE is

.
I'm assuming that you're also supposed to determine the initial value

given this ODE. You have

Given

, you have

but since you already know that

, it follows that

, and in turn that

.