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Sliva [168]
3 years ago
13

What is the value of the algebraic expression if x= 1/2 , y = -1, and z = 2? 6x(y2z) A. -12 B. -6 C. 1 D. 6

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
4 0
To determine the value of the given algebraic expression above, we simply substitute the values of each variable to the variables in the expression and evaluate the expression. We do as follows:

6x(y^2)(z)
      when x = 0.5
                y = -1
                z = 2
6(0.5)((-1)^2)(2)
3(1)(2)
6

The value of the algebraic expression would be 6. An algebraic expression consists of variables which are represented with letters like for this case x, y and z, a coefficient which is indicated by numbers (e.g. 6 ) and exponents like 2 for the expression above. Often times expressions contains a number of terms which consists of those elements.
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What are the solutions to this quadratic equation x2+6x-5=0
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Answer:

See Below.

Explanation:

Quadratic Form:

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Quadratic Formula:

x =  \frac{ - b +   -  \sqrt{ {b}^{2}  - 4ac} }{2a}

Based on the information given from the question, we can deduce:

a = 1

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Now we can substitute all these values into the formula to find x.

x =   \frac{ - 6 +  -  \sqrt{ {6}^{2}  - 4(1)( - 5)} }{2(1)}  \\  =   - 3 +  \sqrt{14}   \: or \:  - 3 -  \sqrt{14}

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To find this out we have to add 5 tens and 13 ones. 
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And 13 ones is equal to 
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good Luck! :)
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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