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Sliva [168]
3 years ago
13

What is the value of the algebraic expression if x= 1/2 , y = -1, and z = 2? 6x(y2z) A. -12 B. -6 C. 1 D. 6

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
4 0
To determine the value of the given algebraic expression above, we simply substitute the values of each variable to the variables in the expression and evaluate the expression. We do as follows:

6x(y^2)(z)
      when x = 0.5
                y = -1
                z = 2
6(0.5)((-1)^2)(2)
3(1)(2)
6

The value of the algebraic expression would be 6. An algebraic expression consists of variables which are represented with letters like for this case x, y and z, a coefficient which is indicated by numbers (e.g. 6 ) and exponents like 2 for the expression above. Often times expressions contains a number of terms which consists of those elements.
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60 POINTS PLEASE HELP FAST!!!! write the equation of a line in standard form that passes through the points (-4,-1) and (1.5,2)
liraira [26]
You find your slope with the equation

(y2-y1)/(x2-x1)

(-1-2)/ -4-1.5)

(-3)/(-5.5)

.54x is your slope

you then plug that into your equation.

y=mx+b

y=.54x+b

you substitute one of our coordinates.

(-4,-1)

-1=.54(-4)+b

-1=-3.45+b

+3.45

2.45=b

your equation is

y=.54x+2.45

standard form


y-.54x=2.45
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Bx%2B1%7D" id="TexFormula1" title="\frac{x}{x+1}" alt="\frac{x}{x+1}" align="a
navik [9.2K]

Answer:

Because i have no more information i assume you would like it to be solved.

x < -1 or -1/3 < x < 1

4 0
3 years ago
halona walks 1.93 kilometers in 23 minutes, assuming constant speed write a proportion that represents how many kilometers in x
Afina-wow [57]
Dividing 1.93km by 23 minutes, you get 0.083 km per minute, or 5.03 km per hour
4 0
3 years ago
What value of b will cause the system to have an infinite number of solutions?
irga5000 [103]

b must be equal to -6  for infinitely many solutions for system of equations y = 6x + b and -3 x+\frac{1}{2} y=-3

<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}

Let us bring the equations in same form for sake of simplicity in comparison

\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}

Now we have two equations  

\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}

Let us first see what is requirement for system of equations have an infinite number of solutions

If  a_{1} x+b_{1} y+c_{1}=0 and a_{2} x+b_{2} y+c_{2}=0 are two equation  

\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}} then the given system of equation has no infinitely many solutions.

In our case,

\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}

 As for infinitely many solutions \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}

\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}

Hence b must be equal to -6 for infinitely many solutions for system of equations y = 6x + b and  -3 x+\frac{1}{2} y=-3

8 0
3 years ago
BD is the angle bisector of
AlexFokin [52]

Note: Let us consider, we need to find the m\angle ABC and m\angle DBC.

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The m\angle ABC and m\angle DBC.

Solution:

BD is the angle bisector of ABC. So,

m\angle ABD=m\angle DBC

3x=x+20

3x-x=20

2x=20

Divide both sides by 2.

x=\dfrac{20}{2}

x=10

Now,

m\angle DBC=(x+20)^\circ

m\angle DBC=(10+20)^\circ

m\angle DBC=30^\circ

And,

m\angle ABC=(3x)^\circ+(x+20)^\circ

m\angle ABC=(4x+20)^\circ

m\angle ABC=(4(10)+20)^\circ

m\angle ABC=(40+20)^\circ

m\angle ABC=60^\circ

Therefore, m\angle DBC=30^\circ,m\angle ABD=30^\circ and m\angle ABC=60^\circ.

8 0
2 years ago
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