-33=-11*3
-8=-11+3
so
(x-11)(x+3)
First of all to make our equation simpler, we'll equal
to a variable like 'a'.
So,
Now let's plug
's value (a) into the equation.
Now we turned our equation into a quadratic equation.
(The variable 'a' will have a solution set of two solutions, but 'x' , which is the variable of our first equation will have a solution set of four solutions since it is a quartic equation (<span>fourth-degree <span>equation) )
Let's solve for a.
The formula used to solve quadratic equations ;
The formula is used in an equation formed like this :
</span></span>
In our equation,
t=16 , b=-41 and c=25
Let's plug the values in the formula to solve.
So the solution set :
We found a's value.
Remember,
So after we found a's solution set, that means.
and
We'll also solve this equations to find x's solution set :)
So the values x has are :
,
,
and
Solution set :
I hope this was clear enough. If not please ask :)
Membership is discounted $2 for first month
c=cost of one month
d=discount=$2
x=# of months
xc - 2= total cost
x for 1 month is 1, c is always 12, -2 is constant
1 x(12) - 2=10 for first month
8 months
8c -2=total cost for 8 months
8 x 12 - 2= 94 for 8 months
Answer:
Cubic expression
Step-by-step explanation:
Polynomials with a degree of 3 are known as cubics.