So to find the answer to this, you have to consider that
- half because half the pocket money (x) was spend on clothes, then plus 9 because that's how much extra she gained and 13 because that was the result of all the changes.
To solve this, first subtract 9 from both side, which leaves you with
and
is the same as
, so to solve this, multiply both sides of the equation by two, resulting in
. SO from this we can conclude that the weekly allowance is $8
Answer:(a) Express the complex number (4 −3i)3 in the form a + bi. (b) Express the below complex number in the form a + bi. 4 + 3i i (5 − 6i) (c) Consider the following matrix. A = 2 + 3i 1 + 4i 3 − 3i 1 − 3i Let B = A−1. Find b22 (i.e., find the entry in row 2, column 2 of A−1)
Step-by-step explanation:
Part A.
Ashwin had a 4-cm cube.
volume of cube = side^3
volume = (4 cm)^3 = 64 cm^3
Ashwin has 64 small cubes.
We need to find the volumes of all prisms in Part A. Only prisms with at most 64 cm^3 volume can be the answer.
A. v = 2 * 4 * 7 = 28
B. v = 4 * 5 * 6 = 120
C. v = 5 * 5 * 4 = 100
D. v = 4 * 7 * 5 = 140
E. v = 3 * 5 * 4 = 60
Part A. answer: A, E
Part B.
Dora had a 5-cm cube.
volume of cube = side^3
volume = (5 cm)^3 = 125 cm^3
Dora has 125 small cubes.
We need to find the volumes of all prisms in Part B. Only prisms with at most 125 cm^3 volume can be the answer.
A. v = 3 * 3 * 8 = 72
B. v = 3 * 4 * 5 = 60
C. v = 6 * 6 * 4 = 144
D. v = 5 * 8 * 4 = 160
E. v = 3 * 5 * 4 = 60
Part B. answer: A, B, E
63 because both angles are the same
Answer:
he grows by 5 cm every year between 1999 and 2006
Step-by-step explanation:
This is a arithmetic progression problem with the formula;
T_n = a + (n - 1)d
We are told that In 1999 Daniel was 146 cm tall. He grew to be 176 cm by the year 2006.
Thus;
a = 146
d = 2006 - 1999 = 7
Thus;
176 = 146 + (7 - 1)d
176 - 146 = 6d
30 = 6d
d = 30/6
d = 5 cm
Thus, he grows by 5 cm every year between 1999 and 2006
