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deff fn [24]
3 years ago
9

In 1999 Daniel was 146 cm tall. He grew to be 176 cm by the year 2006. What was Daniel's rate of growth over this period of his

life? (Find growth each year)
Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
3 0

Answer:

he grows by 5 cm every year between 1999 and 2006

Step-by-step explanation:

This is a arithmetic progression problem with the formula;

T_n = a + (n - 1)d

We are told that In 1999 Daniel was 146 cm tall. He grew to be 176 cm by the year 2006.

Thus;

a = 146

d = 2006 - 1999 = 7

Thus;

176 = 146 + (7 - 1)d

176 - 146 = 6d

30 = 6d

d = 30/6

d = 5 cm

Thus, he grows by 5 cm every year between 1999 and 2006

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Step-by-step explanation:

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The dimensions of a triangular prism are shown below what is the volume of the prism in cubic feet
Yuliya22 [10]

Answer:

B. 192.5 ft³

Step-by-step explanation:

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(5 * 7 * 11)/2

Multiply 5 by 7 to get 35.

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8 0
3 years ago
Someone help me with this question plzzz
asambeis [7]

Answer:

Step-by-step explanation:

As per Janayda,

From the figure attached,

In ΔTRQ,

m∠TRQ + m∠RQT + m∠QTR = 180°

25° + m∠RQT + 35° = 180°

m∠RQT = 180° - 60°

m∠RQT = 120°

Since, m∠RQT + m∠PQT = 180° [Linear pair of angles]

m∠PQT = 180° - m∠RQT

             = 180° - 120°

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In right angled triangle TPQ,

m∠TPQ + m∠PQT + m∠PTQ = 180°

90° + 60° + m∠PTQ = 180°

m∠PTQ = 180° - 150°

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Similarly, other angles can also be evaluated from the given information.

In ΔQTP and ΔNTP,

TP ≅ TP [Reflexive property]

NP ≅ PQ [Given]

ΔQTP ≅ ΔNTP [By LL postulate for congruence]

Therefore, Janayda is correct.

While Sirr is incorrect.

Since, there is not the enough information to prove ΔRTQ and ΔMTN equal, Isabelle is incorrect.

7 0
3 years ago
A submarine travels 168 miles in 7 hours. At this rate, how many miles will the submarine travel in 2 1/2
Damm [24]

Answer:

Step-by-step explanation:

(168 mi)/(7 hr) = (24 mi)/hr

(2.5 hr) × (24 mi)/hr = 60 mi

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