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sashaice [31]
3 years ago
11

(0, 15) (15, 0) (4.8) (10.0) Which ones are solutions

Mathematics
1 answer:
kifflom [539]3 years ago
6 0

Answer:

For which questions dud

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Which of the following conditions make a pair of triangles congruent?
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Answer:

SSS, SAS, ASA, AAS, and HL. These tests describe combinations of congruent sides and/or angles that are used to determine if two triangles are congruent.

Step-by-step explanation:

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3 years ago
Walter buys a bus pass for $30. Every time he rides the bus, money is deducted from the value of the pass. He rode 12 times and
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50cent, 6 divided by 12 is 0.5
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A bucket of paint has spilled on a tile floor. The paint flow can be expressed with the function r(t) = 3t, where t represents t
Anika [276]
R(t) = 3t ; where t represents the time in minutes and r represents how far the paint is spreading.
A(r) = πr²

Part A: 
A[r(t)] = π (3t)² = 3.14 * 9t² = 28.26t²

Part B:
r(10) = 3(10) = 30
A(r) = 3.14 * 30² = 3.14 * 900 = 2,826 square unit

Hope This Helped! :3
7 0
4 years ago
If you figure out these questions I’ll give you brainliest
Naddika [18.5K]

Answer:

1: it is called a building cause it can still be improve or built on.

2: its an integer in a decimal formation.

3: cause each unit is apart from the other units even though it is 1 big building.

Step-by-step explanation:

7 0
3 years ago
Suppose that 600 yards of fencing material are available to fence in
postnew [5]

Answer:

Length = 150 yards

Width = 100 yards

Step-by-step explanation:

We want 600 yards of fencing that will result in the largest 2 fenced corrals, sharing a common border.

It will take the shape of a rectangle, with a dividing fence down the center.

Let W and L,  Width and Length of the larger enclosure.

See attachment.

W= Area of the larger enclosure.

The perimeter is 2W + 2L.

The dividing fence is 1W

We know that we only have 600 yards of fence, so:

2W + 2L + 1W = 600 yards

Area = W x L

---

3W + 2L  = 600    (yards)

2L  = 600 -3W

L = (600-3W)/2

L = 300 -(3/2)W

---

Use this expression in the Area calculation:

Area = W x L

Area = W x (300 -(3/2)W)

Area = 300W -(3/2)W^2)

To find the maximum area, take the first derivative and set to zero to find the value of W that results in the greatest area.

Area' = 300 -2(3/2)W)

0 = 300 - 3W

3W = 300

W = 100 yards

Since 3W + 2L  = 600

L = (600 - 3W)/2

L = (600 - 3(100))/2

L = 150 yards

Area = 150*100 = 15,000 yards^2

 

8 0
3 years ago
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