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sashaice [31]
3 years ago
11

(0, 15) (15, 0) (4.8) (10.0) Which ones are solutions

Mathematics
1 answer:
kifflom [539]3 years ago
6 0

Answer:

For which questions dud

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Suppose x and y vary together such that y = 2 x + 11 . Suppose x varies from x = 2 to x = 8.5 .
Stells [14]

Answer:

a) x changes by 6.5 units

b) y changes by 13 units

Step-by-step explanation:

a. Over this interval, how much does x change by?

Initially, we have that x = 2.

In the end, we have that x = 8.5.

So x changes by 8.5-2 = 6.5 units

b. Over this interval, how much does y change by?

Initially, when x = 2, we have that y = 2x + 11 = 2*2 + 11 = 15

In the end, when x = 8.5, we have that y = 2*8.5 + 11 = 28

So y changes by 28 - 15 = 13 units

8 0
3 years ago
Write an equation for this graph please help me I'm begging u
bekas [8.4K]
First, solve for the slope. This can be found by looking at the y and x intercepts. At x = 0, y = 1.5. At x = 2, y = 0.

Slope is defined as Δy/Δx, or the change in y over the change in x. This means that in order to calculate the slope, you must find the difference between the values of y and divide it by the difference in the values of x for the two points to determine the slope between them.

(0 - 1.5)/(2-0) = (-1.5)/2 = -0.75 or -3/4

Now that you have the slope, we can write the equation in slope intercept form, y = mx + b, where m is the slope we calculated and b is the y intercept, 1.5.

y = (-3/4)x + 1.5
4 0
3 years ago
An angle is 74∘ more than its complement. Find the angle.<br><br> degrees
agasfer [191]
The answer is 16 degrees to your problem.
7 0
3 years ago
Read 2 more answers
What is the value of x?
OlgaM077 [116]

Answer:

I honestly have no clue.

Step-by-step explanation:

I honestly have no clue.

6 0
2 years ago
A toy rocket is launched from the ground straight upward. The height of the rocket above the ground, in feet, is given by the eq
Oksanka [162]

Answer:

Although strictly speaking of mathematics i.e. theoritically,  

t

can take any value from  

{ − ∞ , ∞ ] ,

however, it is essentially a physical problem related to Physics and we cannot have negative  

t  i.e.  t ≥ 0

Further, after the maximum is reached at  t = 2  (observe that first differential is  h ' ( t ) = − 32 t + 64 , which is zero at  t = 2  and second derivative  h ' ' ( t ) = − 32  is negative and at this we have  h ( 2 ) = 64 ), at  t = 4 ,  h ( 4 ) = 0  i.e. toy rocket falls back to the ground and as such, we cannot have  h > 4 .

Hence, domain for  t  is  [ 0 , 4 ] .

tbh google

8 0
3 years ago
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