When a quadratic equation has a repeated solution?
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Answer: <u><em>pls mark as brainliest</em></u>
2x+3y>-3
First we forget the inequality sign
2x+3y=-3
Then we solve for y
3y = -3-2x
3y=-2x-3
y=-\frac{2x}{3}-1
which is of the form y =mx +b
So here slope m is 2/3 and y intercept is -1 .
First we graph .
And then we have to check, which part need to be shaded . And for that , we take a testing point. Let it be (0,0) .
Now we plug this point in the given inequality that is 2(0)+3(0)>-3
0+0>-3
0>-3 which is true. SO we have to shade that part of the graph where point (0,0) belongs .
Step-by-step explanation:
