Answer: 52 and 793.25
Step-by-step explanation:
A translation
(I'm assuming that this isn't multiple choice since you didn't include the answer choices.)
Answer:
An interval that will likely include the proportion of students in the population of twelfth-graders who carry more than $15 is 960
Step-by-step explanation:
For example, Condition 1: n(.05)≤N
• The sample size (10) is less than 5% of the population (millions of musicians), so
the condition is met.
• Condition 2: np(1-p)≥10
• =
2
10
= .2
• 1 − = 10 .2 1 − .2 = 1.6 . This is less than 10 so this condition is not
met.
It would not be practical to construct the confidence interval.
Answer:
X₀ = 71.65
Step-by-step explanation:
given,
mean (μ ) = 64
standard deviation (σ) = 9
σ² = 81
selected candidate are top 20 % candidate
P( X > X₀) = 0.2
P( Z > Z₀) = 0.2
X₀ = 71.65
Hence, the cut off score is equal to X₀ = 71.65
16b^6 sqrt 6a would be the answer
