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malfutka [58]
3 years ago
10

A newspaper writers compensation package includes the total cost of a $150 per month health insurance plan the total cost of a $

55 per month life insurance plan and a salary of 45,000 per year what would the yearly value of the compensation package be
Mathematics
2 answers:
Katyanochek1 [597]3 years ago
8 0

Answer:

<u><em>The answer is</em></u>: <u>$ 47,460.</u>

<u />

Step-by-step explanation:

<em>$ 150 x 12 month health insurance plan</em> = 1800 $

<em>$ 55 x 12 month life insurance plan</em> = $ 660

<em>With an annual salary of</em> $ 45,000 <em>+ Health Insurance</em> $ 1800 <em>+ Life insurance </em>$ 660 = $ 47460

<u><em>The answer is</em></u>: <u>$ 47,460.</u>

Aloiza [94]3 years ago
6 0
150 x 12 = 1800
55 x 12 = 660

1800 + 660 + 45000 = 47,460

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The braking distance, in feet of a car a Travling at v miles per hour is given.
irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

  • The braking distance at 25 mph, is approximately <u>63.7 ft.</u>
  • The braking distance at 55 mph,  is approximately <u>298.35 ft.</u>
  • The braking distance at 85 mph,  is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945  ft.s

D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

450 = 2.6 + \dfrac{v^2}{22}

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

8 0
2 years ago
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Vikentia [17]

230

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6 0
3 years ago
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Help! Math Homework.
Alenkinab [10]
To solve problem 1 what you need to do is figure out how many miles the girls have walked so far and then subtract that from the total distance they must complete.

3/4-(3/10+1/4)

Step 1:Change the denominators so that way they are all the same

3/4=15/20
3/10=6/20              15/20-(6/20+5/20)
1/4=5/20

Step 2: Begin solving the problem

6/20+5/20=11/20
15/20-11/20=4/20

Step 3: Simplify your answer

4/20=1/5

Step 4 (is optional): Write your answer in a complete statement

The three girls walk 1/5mile together to school

Answer: A

I hope this is correct and if not I apologize for giving false information.

8 0
3 years ago
Which of these steps will eliminate a variable in this system? help pls
Nataly [62]
The answer is B. Dbsjskkdjcjdks
4 0
3 years ago
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The prices of 8 sweaters, in dollars, are given.
RSB [31]
First order all the numbers least to greatest.<span>

$28, $28, $30, $31, $35, $36, $41, $43

Because there are two numbers in the middle (no, one middle number).

Add the two together, and divide by 2

31 + 35 = 66

66/2 = 33

</span><span>B.$33 is your answer

hope this helps</span>
8 0
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