Question

If you decide to play a Pick 3 lottery game, in which you have to guess the exact order of the three numbers, what is your probability of winning? All 3 numbers will be between 0 and 9 and can be chosen more than once.

Answer 1

Answer:  The required probability is 0.1%.

Step-by-step explanation:  Given that we have decided to play a Pick 3 lottery game in which we have to guess the exact order of the three numbers.

We are to find the probability of winning.

Let S denotes the sample space for choosing 3 numbers out of 10, .i.e., from 0 to 9. And A denote the event that we chose the exact order of the three numbers.

Since a number can be chosen more than once, so

$n(S)=10\times10\times10=1000,\\\\n(A)=1.$

Therefore, the probability of event A will be

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{1}{1000}=\dfrac{1}{10}\%=0.1\%.$

Thus, the required probability is 0.1%.

Answer 2

Answer:

1/1,000 chance of winning

Step-by-step explanation: