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3 years ago

A 20° sector in a circle has an area of 21.5π yd². What is the area of the circle? Use 3.14 for pi.

Mathematics

2 answers:

baherus [9]3 years ago

8 0

This would be 21.5π * 360 / 20 yd^2 = 1215.18 yd^2 ( using pi = 3.14)

ziro4ka [17]3 years ago

7 0

Answer:

The area of the circle is $1,215.18\ yd^{2}$

Step-by-step explanation:

we know that

The area of a circle is equal to

$A=\pi r^{2}$

$360\°$ subtends the complete circle of area $\pi r^{2}$

by proportion

Find the area of the complete circle if a $20\°$ sector has an area of $21.5\pi\ yd^{2}$

$\frac{x}{360}=\frac{21.5\pi}{20}\\ \\x=360*21.5\pi /20\\ \\x=387\pi \ yd^{2}$

$387\pi \ yd^{2}=387*3.14=1,215.18\ yd^{2}$

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blsea [12.9K]

Answer:

$\textbf{$P(S \cap T) = \frac{89}{90}$ }\\$

Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

Ray UW is the angle bisector of Angle VUT. If the measure of Angle VUW = (4x + 6)° and the measure of Angle WUT = (6x – 10)°, wh

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Answer:

$\huge\boxed{38^{\circ}}$

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An angle bisector divides an angle in half, therefore:

m∠VUW ≅ m∠WUT

Set the expressions equal to each other:

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Subtract 4x from both sides:

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3 years ago

Cassie has test grades of 62, 85 and 89 on the first three tests in herpre-algebra class. What are the possible scores she can m

Vsevolod [243]

Explanation:

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