3 years ago

If pentagon ABCDE is rotated 180° around the origin to create pentagon A′B′C′D′E′, what is the ordered pair of point D′?

Mathematics

2 answers:

Softa [21]3 years ago

4 0

Answer:

Its A (-1,2)

Step-by-step explanation:

180 degree rule is (-x,-y)

point D is (1,-2)

Since the two is already a negative you have to turn it into a positive so that's why it would be (-1,2).

Vesna [10]3 years ago

3 0

Can u include a picture?

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Taya2010 [7]

Answer:

pi/18

Step-by-step explanation:

To change from degrees to radians, we multiply by pi/180

10 * pi/180

pi/18

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3 years ago

Four baskets contain scented soaps. The baskets contain 9, 9, 11, and 15 soaps. If the soaps are divided evenly among the

Elis [28]

Answer:

Step-by-step explanation:

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3 years ago

he has 1/6 of the pie left over. if he shares it with three friends, how much of original pie will each of the four people get?

mario62 [17]

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3 years ago

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Tju [1.3M]

Answer:

Step-by-step explanation:

Rationalize the denominator of b. So, multiply the numerator and denominator by $\sqrt{x}$

$b = \frac{(1-2\sqrt{x}) *\sqrt{x}}{\sqrt{x}*\sqrt{x} }=\frac{1*\sqrt{x} -2\sqrt{x} *\sqrt{x} }{\sqrt{x} *\sqrt{x} }\\\\=\frac{\sqrt{x} -2x}{x}\\$

Now, find a +b

$a +b = \frac{2x+\sqrt{x} }{x}+\frac{\sqrt{x} -2x}{x}\\\\=\frac{2x+\sqrt{x} +\sqrt{x} -2x}{x}$

Combine like terms

$= \frac{2x-2x+\sqrt{x} +\sqrt{x} }{x}\\\\=\frac{2\sqrt{x} }{x}$

Now find (a + b)²

(a +b)² = $(\frac{2\sqrt{x} }{x})^{2}$

$= \frac{2^{2}*(\sqrt{x} )^{2}}{x^{2}}\\\\= \frac{4* x}{x^{2}}\\\\= \frac{4}{x}$

Hint: $\sqrt{x} *\sqrt{x} =\sqrt{x*x}=x$

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2 years ago