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Dmitry [639]
3 years ago
6

Can you help me with this please???

Mathematics
1 answer:
Alecsey [184]3 years ago
4 0
So let’s say you have (2,8) and (4,12)
Your x values are your first ones. So 2 and 4.
that formula is to find the midpoint so let 2 by x1 and 4 be x2. Add those together you get 6. Then divide by 2. Always by 2. You get 3. That’s the midpoint of those two points. Same thing for the y values.
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Jefferson High School is looking to expand its student parking lot by expanding the existing lot as
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brainly.com/question/3577543

This was already answered.

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A fence completely surrounds a pool,that is 30 feet by 10 feet.what is the approximate length,in feet,of the fence
tamaranim1 [39]
Because the fence's dimensions is 30 feet by 10 feet, you can assume that one side of the pool is 30 feet while the other, non-congruent side, is 10 feet. The formula for perimeter, which you are trying to find,  is 2L+2W=P. In this problem, 30 will be your L and 10 will be your W. Therefore, 2(30) +2(10)=80.

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4 0
3 years ago
2. Four pieces of candy are drawn at random from a bag containing five orange pieces and seven brown pieces.
alexandr402 [8]

Answer:

a) 12C4 = \frac{12!}{4! (12-4)!}= \frac{12!}{4! 8!}=\frac{12*11*10*9*8!}{4! 8!}= 495 ways

b) 5C2 = \frac{5!}{2! (5-2)!}= \frac{5!}{2! 3!}=\frac{5*4*3!}{2! 3!}= 10 ways

c) 7C2 = \frac{7!}{2! (7-2)!}= \frac{7!}{2! 5!}=\frac{7*6*5!}{2! 5!}= 21 ways

Step-by-step explanation:

Combinatory means combination or arrangement of different elements.

If we have n total elements and we want to find in how many ways we can select x we can use this general formula:

nCx= \frac{n!}{x! (n-x)!}

Where n! = n *(n-1)!

a. How many different ways can four pieces be selected from the 12 colored pieces?

For this case we have:

12C4 = \frac{12!}{4! (12-4)!}= \frac{12!}{4! 8!}=\frac{12*11*10*9*8!}{4! 8!}= 495 ways

b. How many different ways can two orange pieces be selected from five orange pieces?

For this case we have:

5C2 = \frac{5!}{2! (5-2)!}= \frac{5!}{2! 3!}=\frac{5*4*3!}{2! 3!}= 10 ways

c. How many different ways can two brown pieces be selected from seven brown pieces?

For this case we have:

7C2 = \frac{7!}{2! (7-2)!}= \frac{7!}{2! 5!}=\frac{7*6*5!}{2! 5!}= 21 ways

6 0
4 years ago
Which expression is not equivalent to the other three?
vagabundo [1.1K]

Answer:

b. 4+7x-2

Explanation:

when you add like terms for the first equation it becomes 7x-6

the second one becomes 7x+2

the third one becomes 7x-6

and the last one is also 7x-6

which means the second one is not equivalent

7 0
3 years ago
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